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jek_recluse [69]
3 years ago
11

The distance between the sun and moon is 480 light second. convert the distance into meter​

Physics
1 answer:
prohojiy [21]3 years ago
5 0

Answer:

1.439 × 10¹¹ m is the answer.

Explanation:

1 light-second = 2.998 × 10⁸m

480 light-seconds = 480 × 2.998 × 10⁸

= 1439.04 × 10⁸

= 1.439 × 10¹¹

∴ 1.439 × 10¹¹ m is the answer.

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The braking distance is the distance traveled by a car experiencing a braking force until it comes to rest.

Our initial energy is solely kinetic:
E_i = \frac{1}{2}mv^2

And, since the car goes to rest, it is no longer in motion. It will have no kinetic energy.
E_f = 0

Therefore, there was work done by the braking force.

W_B = E_f - E_i = -\frac{1}{2}mv^2

Recall the definition of work:
W = F\cdot \Delta x

Or in this case, since the displacement and breaking force are antiparallel:
W = -F_B\Delta x

This is equivalent to the dissipation of kinetic energy:
W = -F_B\Delta x = -\frac{1}{2}mv^2

Now, to visualize this, let's rearrange the equation to solve for displacement.

\Delta x =\frac{mv^2}{2F_B}

<u>There is a direct, SQUARE relationship between necessary braking distance speed. </u>

If the speed was reduced by 10.3 percent, its new speed is only 89.7% percent of the original, so:
\Delta x' =\frac{m(0.897v)^2}{2F_B}

\Delta x' = 0.8046\Delta x

The reduction by a percentage is:
1 - 0.8046 = 0.1954 \\\\\boxed{= 19.54\%}

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OlgaM077 [116]

Answer:

a) 0 J

b) W = nRTln(Vf/Vi)

c) ΔQ = nRTln(Vf/Vi)

d) ΔQ = W

Explanation:

a) To find the change in the internal energy you use the 1st law of thermodynamics:

\Delta U=\Delta Q-W

Q: heat transfer

W: work done by the gas

The gas is compressed isothermally, then, there is no change in the internal energy and you have

ΔU = 0 J

b) The work is done by the gas, not over the gas.

The work is given by the following formula:

\\W=nRTln(\frac{V_f}{V_i})

n: moles

R: ideal gas constant

T: constant temperature

Vf: final volume

Vi: initial volume

Vf < Vi, then W < 0 and the work is done on the gas

c) The gas has been compressed. Thus, its temperature increases and heat has been transferred to the gas.

The amount of heat is equal to the work done W

d)

\Delta U = \Delta Q-W\\\\0=\Delta Q-W\\\\\Delta Q=W=nRTln(\frac{V_f}{V_i})

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