<h2>Answer:</h2>
<em>Hello, </em>
<h3><u>Q</u><u>UESTION)</u></h3><em>✔ We have : a = v/Δt </em>
- a = 426/7
- a = 6 m/s²
The car's acceleration is therefore 6 m/s².
A variable that should not change throughout the experiment is a(n):
1 answer:
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Answer:
-22.2 m/s²
Explanation:
The equation for position x for a constant acceleration a, time t and initial velocity v₀, initial position x₀:
(1)
For rocket A the initial and final position: x = x₀= 0. Using these values in equation 1 gives:
(2)
Solving for time t:
(3)
The times for both rockets must be equal, since they start and end at the same location. Using equation 3 for rocket A and B gives:
(4)
Solving equation 4 for acceleration of rocket B:
(5)
Answer with Explanation:
We are given that
Fundamental frequency,f=88.4 Hz
Speed of sound,v=343 m/s
We have to find the first three overtones.
Tube is closed
The overtone of closed pipe is equal to odd number of fundamental frequency.
Therefore, the overtone of tuba
Where n=3,5,7,..
Substitute n=3
For second overtone
For third overtone