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Digiron [165]
3 years ago
12

How many valance electrons does group #11 have?

Chemistry
1 answer:
galina1969 [7]3 years ago
6 0

It would have 11 valance electrons.

Example/Explanation:

Say we are talking about groups 10. Group 10 would have 10 valance electrons because of the atom's electronic arrangement in the periodic table.

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An element has an atomic number of 92 and a mass number of 234, how many neutrons are there?
Sergio039 [100]
Mass number minus atomic number equals neutrons.
234-92=142
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How many electron domains does IF4+ have?
anyanavicka [17]
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A block of wood has the mass of 180 grams.it is 10 cm long,6 cm wide and 4 cm thick.what is it’s density?
DochEvi [55]

Answer:

0.75 g/cm³

Explanation:

Given data:

Mass of wooden block =  180 g

Length of block = 10 cm

Width of block = 6 cm

Height or thickness = 4 cm

Density of block = ?

Solution:

Volume of block = height × length × width

Volume of block = 4 cm × 10 cm× 6 cm

Volume of block = 240 cm³

Density of block:

density = mass/ volume

d = 180 g/ 240 cm³

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3 years ago
A particular exosolar system has five planets in total: A, B, C, D, and E. The table lists the orbital periods of these planets
sveta [45]

Answer:

The answer is in the picture below

Explanation:

8 0
2 years ago
The energy required to ionize boron is 801 kJ/mol. You may want to reference (Pages 93 - 98) Section 2.5 while completing this p
earnstyle [38]

Answer:

The frequency is  f =  2,01 * 10^{15} \  Hz

Explanation:

From the question we are told that

   The energy required to ionize boron is E_b  =  801 KJ/mol

Generally the ionization energy of boron pre atom is mathematically represented as

     E_a  =  \frac{E_b}{N_A}

Here  N_A is the Avogadro's constant with value N_A  =  6.022*10^{23}

So

      E_a  =  \frac{801}{6.022*10^{23}}

=>     E_a  =  1.330 *10^{-18} \  J/atom

Generally the energy required to liberate one electron from an atom is equivalent to the ionization energy per atom and this mathematically represented as

       E =  hf  =  E_a

=>     hf  =  E_a

Here h is the Planks constant with value h = 6.626 *10^{-34}

So

       f =  \frac{1.330 *10^{-18}}{ 6.626 *10^{-34}}

=>      f =  2,01 * 10^{15} \  Hz

8 0
2 years ago
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