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love history [14]
3 years ago
7

How many moles are in 48.1 grams of FeF3?

Chemistry
1 answer:
Sindrei [870]3 years ago
3 0

Answer:

I am not sure which number would be considered correct.

unrounded: 5,427.5559

rounded to the nearest thousandth: 5,427.556

rounded to the nearest hundredth: 5,427.56

rounded to the nearest tenth: 5,427.6

rounded to the nearest whole number: 5,428

Explanation:

112.839 * 48.1 = 5,427.5559

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Which of the following statements is true?
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Its D and A I just took the quick check
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How many moles of ammonium sulfate can be from the reaction of 30.0 mol of NH3 with H2SO4 according to the following equation: 2
marysya [2.9K]

Answer:

15 moles of  ammonium sulfate would be formed from 30 moles of ammonia.

Explanation:

Given data:

Number of moles of ammonium sulfate formed = ?

Number of moles of ammonia = 30.0 mol

Solution:

Chemical equation:

2NH₃  +   H₂SO₄  →  (NH₄)₂SO₄

Now we will compare the moles of ammonium sulfate with ammonia.

                           NH₃           :           (NH₄)₂SO₄

                             2              :               1

                            30.0          :              1/2×30.0 = 15.0 mol

So 15 moles of  ammonium sulfate would be formed from 30 moles of ammonia.

7 0
3 years ago
A transverse wave is traveling from north to south. Which statement could be true for the motion of the wave particles in the me
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<span>C. Their direction of motion is south and north. </span>
7 0
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How many bonds and lone pairs are in the molecule SIH4?
lesantik [10]

Answer:

there are no valence electrons left over, so the molecule has four bond pairs and no lone pairs.

Explanation:

6 0
3 years ago
The compound sodium thiosulfate pentahydrate, Na2S2O3 • 5H2O
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The theoretical yield is 204.4 g while the percent yield is 2.57%.

<h3>What is theoretical yield?</h3>

Theoretical yield is the amount of product obtained based on the stoichiometry of the reaction.

S8(s) + 8 Na2SO3(aq) + 40 H2O(l) --->8 Na2S2O3·5 H2O(s)

Number of moles of sulfur =  3.25 g /8(32) = 0.013 moles

Number of moles of sodium sulfite =  13.1 g/126 g/mol = 0.103 moles

Since 1 moles of sulfur reacts with 8 moles of sodium sulfite

0.013 moles reacts with 0.013 moles ×  8 moles /1 mole = 0.104 moles

There is not enough sodium sulfite hence it is the limiting reactant.

1 mole of sodium sulfite yields 8 moles of product

0.103 moles of sodium sulfite yields  0.103 moles × 8 moles /1 mole = 0.824 moles

Mass of product = 0.824 moles × 248 g/mol = 204.4 g

percent yield =  5.26 g /204.4 g × 100/1

= 2.57%

Learn more about percent yield: brainly.com/question/2506978

4 0
2 years ago
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