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love history [14]
3 years ago
7

How many moles are in 48.1 grams of FeF3?

Chemistry
1 answer:
Sindrei [870]3 years ago
3 0

Answer:

I am not sure which number would be considered correct.

unrounded: 5,427.5559

rounded to the nearest thousandth: 5,427.556

rounded to the nearest hundredth: 5,427.56

rounded to the nearest tenth: 5,427.6

rounded to the nearest whole number: 5,428

Explanation:

112.839 * 48.1 = 5,427.5559

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2 years ago
You need to prepare 100.0 mL of a pH 4.00 buffer solution using 0.100 M benzoic acid (p K a = 4.20 ) and 0.200 M sodium benzoate
bekas [8.4K]

Answer : The volume of sodium benzoate and benzoic acid  solution mixed to prepare this buffer should be, 29.0 mL and 71 mL respectively.

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Let the volume of sodium benzoate (salt) be, x

So, the volume of benzoic acid  (acid) will be, (100 - x)

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

Now put all the given values in this expression, we get:

4.00=4.20+\log \left(\frac{(\frac{0.200x}{100})}{(\frac{0.100(100-x)}{100})}\right)

x = 29.0

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