1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Triss [41]
2 years ago
11

Potassium + water → potassium hydroxide + hydrogen formula

Chemistry
1 answer:
kvasek [131]2 years ago
3 0

Answer:

If you help I'll help you deal?

You might be interested in
What mineral is least important to plant growth
Oksi-84 [34.3K]

Answer:

sodium

Explanation:

nitrogem, phosphorous and potassium are very important to plant growth, but sodium isnt necessary.

7 0
3 years ago
Read 2 more answers
How many grams are in 3.93 x 10^24 molecules of CCl4?
Lorico [155]
<h3>Answer:</h3>

1000 g CCl₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.93 × 10²⁴ molecules CCl₄

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of C - 12.01 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of CCl₄ - 12.01 + 4(35.45) = 153.81 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 3.93 \cdot 10^{24} \ molecules \ CCl_4(\frac{1 \ mol CCl_4}{6.022 \cdot 10^{23} \ molecules \ CCl_4})(\frac{153.81 \ g \ CCl_4}{1 \ mol \ CCl_4})
  2. Multiply:                                                                                                             \displaystyle 1003.77 \ g \ CCl_4

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1003.77 g CCl₄ ≈ 1000 g CCl₄

8 0
3 years ago
The alpha decay of a radioactive nuclide (X) emits a He-4 nucleus and produces an isotope of Superscript 235 subscript 92 upper
kupik [55]

Answer:

Superscript 239 subscript 94 upper P u

(plutonium-239)

Explanation:

In alpha decay, the element subtracts 4 from its mass number and subtracts 2 from its atomic number.

So if we end with Uranium-235, which has an atomic number of 92:

235+4 = 239

92+2 = 94

Element 94 is Pu, plutonium, and its mass could very well be 239 if it's an isotope. So the answer is Superscript 239 subscript 94 upper P u.

7 0
3 years ago
Can you please help me this is due today and I really need help.
valkas [14]
I believe the first blank is inertia
5 0
2 years ago
How to find weight with volume and density ​
stira [4]

Answer:

Explanation:

Look up the density of the material the object is made of in kg/m³.

Measure the volume of the object in m³.

Multiply the density by the volume.

You will then have the mass of the object in kg.

5 0
3 years ago
Other questions:
  • If an element has the atomic number of 117 how many protons will it have and how many electrons will it have
    9·1 answer
  • Give the (Hawarth projection) cyclic
    5·1 answer
  • Metamorphic rocks that melt in a hot fluid can re-crystallize into a different form of rock. true or false
    9·1 answer
  • Soil is best described as a pure substance or a mixture or a compound
    7·1 answer
  • Write the isotope notation for an element with 5 protons and 6 neutrons.
    8·1 answer
  • 2. What is forensic odontology ? Why is this area helpful for investigators?
    13·2 answers
  • Please Help. Thank You!
    15·1 answer
  • Since gasses weigh nothing when they are produced in a reaction they do not have to be accounted for.
    8·1 answer
  • How many atoms are there in each of the following
    6·1 answer
  • Chromium has four naturally occurring isotopes. cr-50 (mass of 49.946 amu and 4.35% abundance); cr-52 (mass of 51.941 amu and 83
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!