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kogti [31]
3 years ago
13

Negative radical in the periodic table​

Chemistry
1 answer:
AVprozaik [17]3 years ago
7 0

Answer:

Negative Radicals ---→

1).Flouride =  F⁻

2). Chloride = Cl⁻

3) Bromide = Br⁻

4) Iodide = I⁻

5) Sulphate = SO₄²⁻

6) Oxide = O²⁻

7) Nitride = N³⁻

8) Sulphur = S²⁻

9) Carbide = C⁴⁻

10) Hydroxide = OH⁻

11) Nitrate = NO₃⁻

12) Carbonate = CO²⁻

13) Hydrogen Carbonate = HCO₃⁻

14) Sulphate = SO₄²⁻

15).Sulphite = SO₃³⁻

16) Nitrate = NO₃⁻

17)Nitrite = NO₂⁻

18) Hydrogen Sulphite = HSO₃⁻

19) Hydrogen Sulphate = HSO₄⁻

20) Chromate = CrO₄²⁻

There are lot of Radicals which cannot be easily written. Although some of the Important Radicals which are commonly used are mentioned above.

Hope it helps,

Please mark me as the brainliest

Thank you

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Kryger [21]

The empirical formula : C₁₂H₄F₇

The molecular formula : C₂₄H₈F₁₄

<h3>Further explanation</h3>

mol C (MW=12 g/mol)

\tt \dfrac{18.24}{12}=1.52

mol H(MW=1 g/mol) :

\tt \dfrac{0.51}{1}=0.51

mol F(MW=19 g/mol)

\tt \dfrac{16.91}{19}=0.89

mol ratio of C : H : O =1.52 : 0.51 : 0.89=3 : 1 : 1.75=12 : 4 : 7

Empirical formula : C₁₂H₄F₇

(Empirical formula)n=molecular formula

( C₁₂H₄F₇)n=562 g/mol

(12.12+4.1+7.19)n=562

(281)n=562⇒ n =2

Molecular formula : C₂₄H₈F₁₄

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3 years ago
Marshall determines that a gas has a gage pressure of 276 kPa. What's the absolute pressure of this gas?
Mariana [72]
C.... 376 tbh just took the test and was right
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3 years ago
Read 2 more answers
John dissolves .5g of a white powder in 25g of benzene (FP 5oC) (kf benzene is 5.1) and finds the solution freezes at 3.7oC. Det
navik [9.2K]

Answer:

The compound has a molar mass of 78.4 g/mol

Explanation:

Step 1: data given

Mass of a sample = 0.5 grams

Mass of benzene = 25 grams

Freezing poing = 5 °C

Kf of benzene = 5.1 °C/m

Freezing point solution = 3.7 °C

Step 2: Calculate molality

ΔT = i*Kf*m

⇒with ΔT = the freezing point depression = 5.0 - 3.7 = 1.3 °C

⇒with i = the can't hoff factor = 1

⇒with Kf = the freezing point depression constant of benzene = 5.1 °C/m

⇒with m = the molality

1.3 = 5.1 * m

m = 1.3 / 5.1

m = 0.255 moles /kg

Step 3: Calculate moles

Molality = moles / mass benzene

0.255 molal = moles / 0.025 kg

Moles = 0.255 molal * 0.025 kg

Moles = 0.006375 moles

Step 4: Calculate molar mass of the compound

Molar mass compund = mass / moles

Molar mass compound = 0.5 grams / 0.006375 moles

Molar mass compound = 78.4 g/mol

The compound has a molar mass of 78.4 g/mol

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