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SashulF [63]
3 years ago
9

Planetesimal definition

Chemistry
2 answers:
Oliga [24]3 years ago
5 0
The term Planetestimal is a minute planet; a body That could or did it come together With many others under gravitation to form a planet. As a adjective it means relating to Planetesimal Bodies . Hope that helped !M
e-lub [12.9K]3 years ago
3 0
A minute planet; a body that could or did come together with many others under gravitation to form a planet.       
adjective1.relating to planetesimal bodies.
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Avogradoa number was calculated by determining the number of atoms in?
Softa [21]

The answer is:

12.00 g of carbon-12.



7 0
3 years ago
Consider the reaction. A(aq) = 2 B(aq) Kc = 6.90 x 10 6 at 500 K If a 3.00 M sample of A is heated to 500 K, what is the concent
kirza4 [7]

Answer:

0.004548 M is the concentration of B at equilibrium at 500 K.

Explanation:

                         A(aq) ⇆ 2 B(aq)

Initially               3.00 M

At equilibrium   3.00 -x    2x

Equilibrium constant of the reaction at 500 K =K_c=6.90\times 10^{-6}

Concentration of A at 500 K at equilibrium , [A] = (3.00 -x )M

Concentration of B at 500 K at equilibrium,[B]= 2x

An expression of equilibrium constant is given as:

K_c=\frac{[B]^2}{[A]}

6.90\times 10^{-6}=\frac{4x^2}{(3.00-x)}

On solving for x:

x = 0.002274 M

[B] = 2 x = 2 × 0.002274 M = 0.004548 M

[A] = (3-x) = 3 M - 0.002274 M =2.997726 M

0.004548 M is the concentration of B at equilibrium.

8 0
3 years ago
NH3 + CO2 + H2O → NH4HCO3 Balance this reaction if necessary. A) balanced B) 1, 1, 2, 1 C) 1, 2, 1, 2 D) 1, 2, 2, 2
Julli [10]

Answer:

NH3 + CO2 + H2O -> NH4HCO3

This equation is already balanced

4 0
3 years ago
Read 2 more answers
What kind of phase transition will occur when energy is continuously supplied to a solid sample?
Annette [7]
The correct answer should be C. Melting because if energy such as thermal energy is supplied to a solid such as ice then it would melt
5 0
3 years ago
Read 2 more answers
What volume (in L) of a 6.84 M.
grandymaker [24]

Answer:

0.158L

Explanation:

From the question, we obtained the following information:

C1 = 6.84 M

V1 =?

C2 = 1.84 M

V2 = 588 mL = 588/1000 = 0.588L

Using the dilution formula C1V1 = C2V2. The original volume can calculated for as follows:

C1V1 = C2V2

6.84 x V1 = 1.84 x 0.588

Divide both side by 6.84

V1 =(1.84 x 0.588) / 6.84

V1 = 0.158L

4 0
3 years ago
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