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klasskru [66]
3 years ago
15

A 10.11 g sample of NaBr contains 22.34 % Na by mass. Considering the law of constant composition (definite proportions), how ma

ny grams of sodium does a 7.09 g sample of sodium bromide contain
Chemistry
1 answer:
Ksenya-84 [330]3 years ago
8 0

Answer:

1.58\ \text{g}

Explanation:

10.11 g sample of NaBr contains 22.34% Na by mass

According to the law of constant composition the if one sample of NaBr has 22.34% of Na by mass then any other sample of NaBr will have the same percentage of the amount of Na.

For a sample of 7.09 g we have

7.09\times \dfrac{22.34}{100}=1.583906\approx 1.58\ \text{g}

The mass of sodium in the required sample is 1.58\ \text{g}.

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A chemist must dilute 61.9 mL of 548. nM aqueous sodium carbonate (Na2CO3) solution until the concentration falls to 484. nM . H
maw [93]

Answer:

The final volume will be "70.08 mL".

Explanation:

The given values are:

Molar mass,

M1 = 548 nM

or,

     = 5.48\times 10^{-7} \ M

M2 = 484 nM

or,

      = 4.84\times 10^{-7} \ M  

Volume,

V1 = 61.9 mL

V1 = ?

By using the expression, we get

⇒ M1\times V1=M2\times V2

or,

⇒            V2=\frac{M1\times V1}{M2}

By substituting the values, we get

                    =\frac{5.48\times 10^{-7}\times 61.9}{4.84\times 10^{-7}}

                    =\frac{339.212}{4.84}

                    =70.08 \ mL

7 0
3 years ago
Solid solutions where one metal is dissolved in another is known as a(n) _____________.
krok68 [10]

Answer:

ionic solution

Explanation:

when is dissleves its ionic

8 0
3 years ago
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telo118 [61]

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The reaction is photo-catalyzed and would only take place in the presence of sunlight.

6CO₂ + 6H₂O + sunlight → C₆H₁₂O₆ + 6O₂

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3 years ago
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3 0
3 years ago
What charge (positive, negative, neutral) does the complete atom<br> have?
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