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klasskru [66]
3 years ago
15

A 10.11 g sample of NaBr contains 22.34 % Na by mass. Considering the law of constant composition (definite proportions), how ma

ny grams of sodium does a 7.09 g sample of sodium bromide contain
Chemistry
1 answer:
Ksenya-84 [330]3 years ago
8 0

Answer:

1.58\ \text{g}

Explanation:

10.11 g sample of NaBr contains 22.34% Na by mass

According to the law of constant composition the if one sample of NaBr has 22.34% of Na by mass then any other sample of NaBr will have the same percentage of the amount of Na.

For a sample of 7.09 g we have

7.09\times \dfrac{22.34}{100}=1.583906\approx 1.58\ \text{g}

The mass of sodium in the required sample is 1.58\ \text{g}.

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How many grams of iron can be made with 21.5g of Fe2O3
SIZIF [17.4K]

The mass (in grams) of iron, Fe that can be made from 21.5 g of Fe₂O₃ is 15.04 g

We'll begin by writing the balanced equation for the reaction. This is given below:

2Fe₂O₃ -> 4Fe + 3O₂

  • Molar mass of Fe₂O₃ = 159.7 g/mol
  • Mass of Fe₂O₃ from the balanced equation = 2 × 159.7 = 319.4 g
  • Molar mass of Fe = 55.85 g/mol
  • Mass of Fe from the balanced equation = 4 × 55.85 = 223.4 g

From the balanced equation above,

319.4 g of Fe₂O₃ decomposed to produce 223.4 g of Fe

<h3>How to determine the mass of iron, Fe produced</h3>

From the balanced equation above,

319.4 g of Fe₂O₃ decomposed to produce 223.4 g of Fe

Therefore,

21.5 g of Fe₂O₃ will decompose to produce = (21.5 × 223.4) / 319.4 = 15.04 g of Fe

Thus, 15.04 g of Fe were produced.

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5 0
1 year ago
A rod shaped organism with no nucleus commonly found in Garbage will most likely belong to which kingdom
Dovator [93]

Answer:

Monera

Explanation:

This organism is only bacteria (bacilli bacteria). They are simple unicellular organism; they have no nucleus. They barely have organelles. These organism in the garbage are heterotrophic /saprophytic and cause the composition of the organic molecules (such as the discarded foods).  

8 0
3 years ago
An experiment to measure the enthalpy change for the reaction of aqueous
Komok [63]

Given that, an experiment to measure the enthalpy change for the reaction of aqueous copper(II) sulfate, CuSO4(aq) and zinc, Zn(s) was carried out in a coffee cup calorimeter; the heat of the reaction in the whole system is calculated to be 2218.34 kJ

Heat of reaction (i.e enthalpy of reaction) is the quantity of heat that is required to be added or removed when a chemical reaction is taken place in order to maintain all of the compounds present at the same temperature.

The formula used to calculate the heat of the reaction can be expressed as follows:

Q = mcΔT

where:

  • Q = quantity of heat transfer
  • m = mass
  • c = specific heat of water = 4.18 kJ/g °C (constant)
  • ΔT = change in temparature

From the information given:

  • The initial temperature (T₁) = 25° C
  • The final temperature (T₂) = 91.5° C

∴

The change in temperature i.e. ΔT = T₂ - T₁

ΔT = 91.5° C - 25° C

ΔT = 66.5° C

The number of moles of CuSO₄ = 1.00 mol/dm³ × 50.0 cm³

\mathbf{= (1 \times \dfrac{50}{1000})\ moles}

= 0.05 moles

  • Since the molar mass of CuSO₄ = 159.609 g/mol

Then;

Using the relation:

\mathbf{number \ of \ moles = \dfrac{mass}{molar \ mass}}}

By crossing multiplying;

mass of CuSO₄ = number of moles of CuSO₄ ×  molar mass of CuSO₄

mass of CuSO₄ = 0.05 moles  × 159.609 g/moles

mass of CuSO₄ = 7.9805 grams

∴

Using the formula from above:

Q = mcΔT

Q = 7.9805 g × 4.18 kJ/g °C × 66.5° C

Q = 2218.34 kJ

Therefore, we can conclude that the heat of the reaction is 2218.34 kJ

Learn more about the chemical reaction here:

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8 0
3 years ago
What is the density of an 84.7 g sample of an unknown substance if the sample occupies 49.6cm cubed
Ahat [919]

Answer:

             1.70 g.cm⁻³

Solution:

Data Given;

                   Mass  =  84.7 g

                   Volume  =  49.6 cm³

                   Density  =  ?

Formula Used;

                   Density  =  Mass ÷ Volume

Putting values,

                   Density  =  84.7 g ÷ 49.6 cm³ 

                   Density  =  1.70 g.cm⁻³

7 0
3 years ago
Na + Cl --&gt; NaCl
dalvyx [7]

Answer:

38.152 g NaCl would be produced.

Explanation:

\frac{(23 + 35.5) \times 15}{23}  \\  = 38.152 \:  \: g

<u>M</u><u>a</u><u>r</u><u>k</u><u> </u><u>me</u><u> </u><u>as</u><u> </u><u>Brainliest</u><u> </u>

5 0
3 years ago
Read 2 more answers
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