Answer:
Your answer will be "Over the ocean"
Explanation:
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Answer:
.6250 M
The Sodium Hydroxide is the solute, and the water is the solvent.
Explanation:
mol/volume= Molarity
(25/22.99+16+1.008)/1=.6250 M.
LiOH, LiNO₂, LiHCO₃, Li₂SO₃, Li₂HPO₄
Silicon is a popular semi-conductor. The process of doping either creates an excess or lack of electrons. In the case of silicon, the dopant is arsenic which has greater valence electron than silicon. Arsenic then donates an electron resulting to an excess of electrons. A new type or better type of semi-conductor is created. Silicon conduct greater electricity.
The best answer is the last option.
Answer:
The answer is 0.75M HCl
Explanation:
To calculate the concentration of 10 ml of HCl that would be required to neutralize 50.0 mL of 0.150 M NaOH, we use the formula:
To calculate the concentration of 10 ml of HCl that would be required to neutralize 50.0 mL of 0.150 M NaOH, we use the formula:
C1V1 = C2V2
C1 = concentration of acid
C2 = concentration of base
V1 = volume of acid
V2 = volume of base
From the information supplied in the question:
concentration of acid (HCl) is the unknown
volume of acid (HCl) = 10ml
concentration of base (NaOH) = 0.15M
volume of base (NaOH) = 50ml
C1 x 10ml = 0.15M x 50ml
C1 x 10 = 7.5
divide both side by 10
C1 = 0.75M
concentration of acid (HCl) is 0.75M
