Answer:
0.027 mole of NaOH.
Explanation:
We'll begin by obtaining the number of mole H2SeO4 in 45mL of 0.30M H2SeO4
This is illustrated below:
Molarity of H2SeO4 = 0.3M
Volume of solution = 45mL = 45/1000 = 0.045L
Mole of H2SeO4 =...?
Mole = Molarity x Volume
Mole of H2SeO4 = 0.3 x 0.045
Mole of H2SeO4 = 0.0135 mole
Next, the balanced equation for the reaction. This is given below:
H2SeO4 + 2NaOH –> Na2SeO4 + 2H2O
From the balanced equation above,
1 mole of H2SeO4 required 2 moles of NaOH.
Therefore, 0.0135 mole of H2SeO4 will require = 0.0135 x 2 = 0.027 mole of NaOH.
Therefore, 0.027 mole of NaOH is needed for the reaction.
Answer: Stock nomenclature of 
is ammonium(I) nitrate
Explanation:
Stock nomenclature is used for chemical nomenclature where the oxidation states of some or all of the elements in a compound are indicated by Roman numerals in parentheses.
For example:
which has iron in oxidation state of +2 has stock nomenclature of iron(II) chloride.
which has iron in oxidation state of +3 has stock nomenclature of iron(III) chloride.
Thus the stock nomenclature of is ammonium(I) nitrate as ammonium has oxidation state of +1.
