1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
garik1379 [7]
2 years ago
10

What are the coordinates of the point (-9, 4) after a 90 degree rotation followed by a translation 3 units right?

Mathematics
2 answers:
hammer [34]2 years ago
4 0
The answer isssss : (-9,1)
oksian1 [2.3K]2 years ago
3 0
(-9,1) should be the answer not completely sure tho
You might be interested in
The sum of person x and person y is 2640. if person x's income is 20% more than person y, find person x's income.
Masja [62]

Answer:

I do not understand she question do you mean the sum of their income is 2640

if so, then the answer is 440 to be x income

Step-by-step explanation:

x income = 20% or 1/5 of y income

y income = 5 of x income

we know that the sum of their income = 2640

which means that

x + y = 2640 =

1/5y + y = 2640

6y/5 = 2640

cross multiply to give us

6y = 5(2640)

6y = 13200

divide through by 6 to give us,

6y/6 = 13200/6

y = 2200

since we know that x income is 20% y income,

therefore, x income =

20/100 * 2200

= 440

therefore,

x income = 440

y income = 2200

5 0
2 years ago
Read 2 more answers
Use the given information to find the new price. Round to the nearest cent.
sesenic [268]

Answer:

Step-by-step explanation:

7.84 = 8.

3 0
2 years ago
Read 2 more answers
Solve using long division <br> Please
madreJ [45]

1. Solution,\frac{2x^3+4x^2-5}{x+3}:\quad 2x^2-2x+6-\frac{23}{x+3}

Steps:

\mathrm{Divide}\:\frac{2x^3+4x^2-5}{x+3}:\quad \frac{2x^3+4x^2-5}{x+3}=2x^2+\frac{-2x^2-5}{x+3}

\mathrm{Divide}\:\frac{-2x^2-5}{x+3}:\quad \frac{-2x^2-5}{x+3}=-2x+\frac{6x-5}{x+3}

\mathrm{Divide}\:\frac{6x-5}{x+3}:\quad \frac{6x-5}{x+3}=6+\frac{-23}{x+3}

\mathrm{Simplify}, =2x^2-2x+6-\frac{23}{x+3}

\mathrm{The\:Correct\:Answer\:is\:2x^2-2x+6-\frac{23}{x+3}}

2. Solution, \frac{4x^3-2x^2-3}{2x^2-1}:\quad 2x-1+\frac{2x-4}{2x^2-1}

Steps:

\mathrm{Divide}\:\frac{4x^3-2x^2-3}{2x^2-1}:\quad \frac{4x^3-2x^2-3}{2x^2-1}=2x+\frac{-2x^2+2x-3}{2x^2-1}

\mathrm{Divide}\:\frac{-2x^2+2x-3}{2x^2-1}:\quad \frac{-2x^2+2x-3}{2x^2-1}=-1+\frac{2x-4}{2x^2-1}

\mathrm{The\:Correct\:Answer\:is\:2x-1+\frac{2x-4}{2x^2-1}}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

4 0
3 years ago
How much simple interest would $1 ,400 earn in 12 months at an interest rate of 3.25%?
goldfiish [28.3K]

Answer:

$45.50

Step-by-step explanation:

Interest = Principal x rate x time (in years)

I = 1400 x .0325 x 1

3 0
3 years ago
Read 2 more answers
What is the area? Bit confused on this one.
DENIUS [597]

Answer:

x² + 8x + 12

Step-by-step explanation:

see

the length of the entire rectangle = x + 6

breadth of the entire rectangle = x + 2

area of a rectangle = length × breadth

= (x + 6)(x + 2)

= x² + 8x + 12

which is the required polynomial in standard form

7 0
2 years ago
Read 2 more answers
Other questions:
  • Please help I don’t know how to simplify this
    15·1 answer
  • Sin 20.sin 10 as sum or difference
    12·1 answer
  • Leanne multiplied 8 x 4.3 and got 32.24. Is Leanne correct?Use an area model to explain your answer
    9·1 answer
  • HELP!!!!!plz!!!!!!ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
    8·1 answer
  • Jeremy bought 5.6 pounds of chocolate. Jeremy's friend Susan bought twice as much chocolate as he did. How much more chocolate d
    9·1 answer
  • Can somebody help me with this (NUMBER 3)
    5·1 answer
  • Secant and Tangent Angles in circles. <br>Solve for x.<br>​
    10·2 answers
  • Question 1:
    7·1 answer
  • If complex number z = 3 Left-bracket cosine (StartFraction 3 pi Over 2 EndFraction) + I sine (StartFraction 3 pi Over 2 EndFract
    11·2 answers
  • Please help me answer! <br> Name the angle pair and find the missing angle measure
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!