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lana66690 [7]
3 years ago
7

Could someone please help me out with this problem? Thank you so much!! :)

Physics
1 answer:
IRINA_888 [86]3 years ago
4 0

Answer:

67.17 m

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 32 m/s

Angle of projection (θ) = 20°

Acceleration due to gravity (g) = 9.8 m/s²

Range (R) =?

The range can be obtained as follow:

R = u²Sine 2θ / g

R = 32² × Sine (2×20) / 9.8

R = 1024 × Sine 40 / 9.8

R = (1024 × 0.6428) / 9.8

R = 67.17 m

Thus, the range of the ball is 67.17 m

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