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3 years ago

What is the slope of (7,9.5) (2,7)

Mathematics

2 answers:

tensa zangetsu [6.8K]3 years ago

8 0

Answer: m=0.5

Step-by-step explanation:

Let's find the slope between your two points.

(7,9.5);(2,7)

(x1,y1)=(7,9.5)

(x2,y2)=(2,7)

Use the slope formula:

m=Let's find the slope between your two points.

(7,9.5);(2,7)

(x1,y1)=(7,9.5)

(x2,y2)=(2,7)

Use the slope formula:

y2−y1/y2−y1

7−9.5/2-7

2.5/-5 m=0.5

love history [14]3 years ago

7 0

Answer:

$\displaystyle m=0.5$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)
Slope Formula: $\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Point (7, 9.5)

Point (2, 7)

Step 2: Find slope m

Simply plug in the 2 coordinates into the slope formula to find slope m

Substitute in points [Slope Formula]: $\displaystyle m=\frac{7-9.5}{2-7}$
[Fraction] Subtract: $\displaystyle m=\frac{-2.5}{-5}$
[Fraction] Divide: $\displaystyle m=0.5$

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I am having trouble with this relative minimum of this equation.

Norma-Jean [14]

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So the approximate relative minimum is (0.4,-58.5).

Step-by-step explanation:

Ok this is a calculus approach. You have to let me know if you want this done another way.

Here are some rules I'm going to use:

$(f+g)'=f'+g'$ (Sum rule)

$(cf)'=c(f)'$ (Constant multiple rule)

$(x^n)'=nx^{n-1}$ (Power rule)

$(c)'=0$ (Constant rule)

$(x)'=1$ (Slope of y=x is 1)

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$y'=(4x^3+13x^2-12x-56)'$

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$y'=4(3x^2)+13(2x^1)-12(1)$

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Now we set y' equal to 0 and solve for the critical numbers.

$12x^2+26x-12=0$

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$6x^2+13x-6=0$

Compaer $6x^2+13x-6=0$ to $ax^2+bx+c=0$ to determine the values for $a=6,b=13,c=-6$ .

$a=6$

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$c=-6$

We are going to use the quadratic formula to solve for our critical numbers, x.

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

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$x=\frac{-13 \pm \sqrt{169+144}}{12}$

$x=\frac{-13 \pm \sqrt{313}}{12}$

Let's separate the choices:

$x=\frac{-13+\sqrt{313}}{12} \text{ or } \frac{-13-\sqrt{313}}{12}$

Let's approximate both of these:

$x=0.3909838 \text{ or } -2.5576505$ .

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The relative maximum is at approximately -2.5576505.

So the relative minimum is at approximate 0.3909838.

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