Answer:
Examples of substances insoluble in water: oil, acetone, ether
Explanation:
Such examples of substances are non-polar and do not dissolve in water (polar compound). The classic example is oil floating in water (this happens because oil has a lower density than water).
I believe the correct order of words should be:
Counterclockwise
Crescent
Full
Half
Faces?
Waxing
Right
Waning
Left
I am not sure on faces, but I don't see any other words from the bank that would fit that description. Hope these are correct and hope I helped!
<span>Density is a value for
mass, such as kg, divided by a value for volume, such as m3. Density is a
physical property of a substance that represents the mass of that substance per
unit volume. For gases we use the ideal gas equation to solve for density. We do as follows:
PV = nRT
PV = mRT / MM
Density = m/V = PMM / RT
From the conditions given of the O2 system we can determine P/RT as follows:
P/RT = density / MM = 1.30 / 32
P/RT = 0.0406
density of propane = 0.0406 x 44.11 = 1.79 g/L</span>
Answer:
see below
Explanation:
[H₃O⁺] = 10^-pH
a) Soln X with pH = 4.9 => [H₃O⁺] = 10⁻⁴°⁹ = 2.51 x 10⁻⁵M
b) Soln Y with pH = 7.4 => [H₃O⁺] = 10⁻⁷°⁴ = 3.98 x 10⁻⁸M
Answer:
34545 J
Explanation:
Applying,
E = mc'+cm(t₂-t₁)+Cm(t₂-t₀).............. Equation 1
Where E = Total energy, m = mass of the ice, c' = latent heat of ice, c = specific heat capacity of ice, t₂ = final temperature, t₁ = initial temperature, C = specific heat capacity of water, t₀ = temperature of ice at 0°C
From the question,
Given: m = 35 g = 0.035 kg, t₁ = -10°C, t₂ = 100°C, t₀ = 0°C
Constant: C = 4200 J/kg.K, c = 2100 J/kg.K, c' = 336000 J/kg
Susbtitute these values into equation 1
E = [336000(0.035)]+[0.035×2100(100+10)]+[4200×0.035(100-0)]
E = 11760+8085+14700
E = 34545 J