The Electron Affinity(EA) tends to _________ as the atomic number increases In any group.

According to the United States Department of Agriculture (USDA), Texas had 4 , 015 , 000 beef cows in 2013 . If one cow produces

marishachu [46]

Answer:

3.00 × 10¹¹ g

Explanation:

According to the United States Department of Agriculture (USDA), Texas had 4,015,000 beef cows in 2013. One beef cow produces 205 grams of methane per day. The methane produced by the beef cows in Texas per day is:

$4,015,000Cow \times \frac{205gCH_4}{cow \times day} = \frac{8.23 \times 10^{8}gCH_4}{day}$

Each year has 365 days. The methane produced by the beef cows in Texas per year is:

$\frac{8.23 \times 10^{8}gCH_4}{day} \times \frac{365day}{1y} = 3.00 \times 10^{11}gCH_4$

5 0

4 years ago

What is the percent by mass of carbon in acetone c3h6o

Volgvan

Well, the molar mass of acetone would be

3(12.011)+6(1.008)+15.999 , which cleans up to be 58.08 grams.

out of this total, 3(12.011), or 36.033 grams are carbon

So, to find the percent, you do part over whole

36.033/58.08, which equals 0.6204 with significant figures

multiply that by 100 to get 62.04%

Hope that helps!

7 0

3 years ago

Read 2 more answers

A saturated solution of Al(OH)3 has a molar solubility of2.9x J0-9 Mat a certain temperature. What is the solubility product con

Viktor [21]

The solubility product constant, Ksp, of the aluminum hydroxide, Al(OH)₃ at the temperature is 1.91×10¯³⁹

<h3>What is solubility of product? </h3>

The solubility of product (Ksp) is defined as the concentration of products raised to their coefficient coefficients. This is illustrated below:

mA <=> nC + eD

Ksp = [C]^n × [D]^e

With the above information in mind, we can obtain the solubility of the product. This is illustrated below:

<h3>Dissociation equation </h3>

Al(OH)₃(aq) → Al³⁺(aq) + 3OH¯(aq)

From the balanced equation above,

1 mole of Al(OH)₃ contains 1 mole of Al³⁺ and 3 moles of OH¯

<h3>How to determine the concentration of Al³⁺ and OH¯</h3>

From the balanced equation above,

1 mole of Al(OH)₃ contains 1 mole of Al³⁺ and 3 moles of OH¯

Therefore,

2.9×10¯⁹ M Al(OH)₃ will also contain

1 × 2.9×10¯⁹ = 2.9×10¯⁹ M Al³⁺
3 × 2.9×10¯⁹ = 8.7×10¯⁹ M OH¯

<h3>How to determine the solubility of product </h3>

Concentration of Al³⁺ = 2.9×10¯⁹ M

Concentration of OH¯ = 8.7×10¯⁹ M

Solubility product (Ksp) =?

Al(OH)₃(aq) → Al³⁺(aq) + 3OH¯(aq)

Ksp = [Al³⁺] × [OH¯]³

Ksp = 2.9×10¯⁹ × (8.7×10¯⁹)³

Ksp = 1.91×10¯³⁹

Learn more about solubility of product:

brainly.com/question/4530083

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5 0

3 years ago

Please answer asap!

kaheart [24]

200 ml is 1/5 of a liter, so the answer is five times the number of moles present in the solution. 0.6 moles/0.2 liter = x moles/1.0 liter. Solving for x gives 0.2 x = 0.6 or x = 3.0 M

so the answer is c

3 0

3 years ago

The decomposition of potassium chlorate yields oxygen gas. If the yield is 895%, how many grams of KClO3 are needed to produce 1

harina [27]

The answer is either 38 g or 40.g KCLO3. If it 95% instead of 895%.

4 0

3 years ago