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AlekseyPX
2 years ago
6

Can force be two-dimensional?

Physics
1 answer:
nata0808 [166]2 years ago
3 0

Answer:

Yes

Explanation:

Just as motion in two dimensions introduced vectors, forces in two dimensions also involve more involved issues. 

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Which process is represented by the PV diagram shown below?
MrMuchimi

Answer: B. the isovolumetric process

Explanation:

In the graph given, the volume is constant throughout. It represents a constant volume process. Such processes are called the isovolumetric process or isochoric process.

<em>Hence, option B is the correct answer.</em>

Option A is incorrect because in an isobaric process, the pressure is constant.

Option C is incorrect because in an isothermal process, the temperature is constant.

Option D is incorrect because in an adiabatic process there is no heat transfer.

8 0
3 years ago
What is the difference between the initial position and the final position of an object?
Grace [21]
The initial is where you are starting and the final postion is where the object ends up
5 0
3 years ago
If light travels from oil (slower medium) to water (faster medium) at an angle, what happens to the direction of the light ray i
iVinArrow [24]
If light travels from oil to water at an angle, what happens to the direction of the light ray in water with respect to the normal, is it moves away from the normal.
7 0
3 years ago
Light with an intensity of 1 kW/m2 falls normally on a surface and is completely absorbed. The radiation pressure is
kobusy [5.1K]

Answer:

The radiation pressure of the light is 3.33 x 10⁻⁶ Pa.

Explanation:

Given;

intensity of light, I = 1 kW/m²

The radiation pressure of light is given as;

Radiation \ Pressure = \frac{Flux \ density}{Speed \ of \ light}

I kW = 1000 J/s

The energy flux density = 1000 J/m².s

The speed of light = 3 x 10⁸ m/s

Thus, the radiation pressure of the light is calculated as;

Radiation \ pressure = \frac{1000}{3*10^{8}} \\\\Radiation \ pressure =3.33*10^{-6} \ Pa

Therefore, the radiation pressure of the light is 3.33 x 10⁻⁶ Pa.

6 0
3 years ago
What is the kinetic energy of a 0.25kg ball rolling at a speed of 2.5m/s
Lisa [10]

Answer:

Explanation:

Kinetic Energy formula:

KE = \frac{1}{2}mv²

m=mass

v=speed

Given:

m=0.25kg

v=2.5m/s

Plug the values in:

KE = 1/2(0.25kg)(2.5m/s)²

KE = 0.78125 J (Joules)

4 0
2 years ago
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