Can force be two-dimensional?
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We conclude that Jeremy walked 2.37km North and 0.59 km West.
<h3>How to get the North and West components?</h3>
We can assume that the distance that he walked is the hypotenuse of a right triangle, like the one you can see in the image below.
There, you can see that the adjacent cathetus would be the displacement in the North direction, while the opposite cathetus would be the displacement in the West direction.
Then we can use the relations.
- Sin(θ) = (opposite cathetus)/(hypotenuse)
- Cos(θ) = (adacent cathetus)/(hypotenuse).
With θ = 13.9° and hypotenuse = 2.44km
Solving these two we will get:
sin(13.9°) = Y/2.44km
sin(13.9°)*2.44km = Y = 0.59 km
cos(13.9°) = X/2.44km
cos(13.9°)*2.44km = X = 2.37km
So we can conclude that he walked 2.37km North and 0.59 km West.
If you want to learn more about right triangles, you can read:
