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loris [4]
4 years ago
5

If an object only reflects ultraviolet photons, what color would it look to us? white a) black b)c) redclear d)violet e)

Physics
1 answer:
xenn [34]4 years ago
4 0

Answer:

The correct answer is option 'b': Black

Explanation:

As we know that the color that our eye perceives is the color of the component of the visible light that the object reflects. It means that if an object reflects wavelength of red light when white light is incident on it it will appear to be red.

in our case it is given that the object absorbs all the wavelengths of the visible light spectrum thus it will appear as black to our eye.

Now since our eyes cannot sense the ultraviolet spectrum of light thus we cannot observe any difference if the object emitted the UV radiation or not. Hence the object will appear to be black.

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A bowling ball rolls off the edge of a cliff, moving horizontally at 20 m/s. I have to plot the position of the bowling ball on
liubo4ka [24]
For counting x you use simple equation for the distance covered by the object when it moves with constant velocity:
s=v*t
that gives you 20m after 1st second, 40 m after 2nd second, 60 m after 3rd second and so on.

For counting y you have to use the equation for the distanced covered by the object moving with constantly accelerating velocity (symbols refering to vertical movement):
h=g\frac{t^{2}}{2}
that gives you 5m after 1st second, 20m afters 2nd second, 45m after 3rd second and so on.
Add minus signs before y positions to receive graph presenting the movement of the ball.
So the points are: P1=[20,-5], P2=[40,-20], P3=[60,-45] and so on... Pn=[x,y].
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WINSTONCH [101]
I believe the answer is true
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A kangaroo jumps up with an initial velocity of 36 feet persecond from the ground (assume its starting height is 0 feet).Use the
kkurt [141]

Given

Initial velocity:

36 ft/s

Initial height:

0 ft

Vertical motion model:

h(t) = -16t^2 + ut + s

v = initial velocity

s = is the height

Procedure

We are going to use the model provided for the vertical motion.

\begin{gathered} h(t)=-16t^2+36t+0 \\ h(t)=-16t^2+36t \end{gathered}

We know that at the maximum height the final velocity is 0.

Then we will use the following expression to calculate the maximum height:

\begin{gathered} v^2_f=v^2_o-2ah_{\max } \\ 0=v^2_o-2ah_{\max } \\ 2ah_{\max }=v^2_o \\ h_{\max }=\frac{v^2_o}{2a} \\ h_{\max }=\frac{(36ft/s)^2}{2\cdot32ft/s^2} \\ h_{\max }=20.25\text{ ft} \end{gathered}

Now for time:

\begin{gathered} 20.25=-16t^2+36t \\ 16t^2-36t+20.25=0 \end{gathered}

Solving for t,

\begin{gathered} t_1=2.25 \\ t_2=0 \end{gathered}

The total time the kangaroo takes in the air is 2.3s.

3 0
1 year ago
How long does it take for earth to complete one full rotation?
Gwar [14]

Answer:

23 hours 56 minutes 4.091 seconds

Explanation:

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