Answer:
69.7173 u
Explanation:
The abundance of the first isotope is =60.40%
So the abundance of the second isotope =100%-60.40%=39.6%
Atomic mass of first isotope = 68.9257
So the average atomic mass of the first isotope =68.9257×0.6040=41.6311 u
Atomic mass of the second isotope =70.9249 u
So average atomic mass of second isotope =70.9249×0.396=28.086
Now the average atomic mass =41.6311+28.086=69.7173 u
Answer: The sun’s radiation consists of small, massless packets of energy called photons. They travel seamlessly through space; whenever they strike any object, the object absorbs photons and its energy is increased, which then heats it up.
Explanation:
Answer: The correct answer is option (C).
Explanation:
As it is given in the problem, the path of a meteor passing Earth is affected by its gravitational force and falls to Earth's surface. Another meteor of the same mass falls to Jupiter's surface due to its gravitational force.
According to Newton's law of universal gravitational, every particle attracts every other particles in the universe with the gravitational force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
The Jupiter is the most massive planet in the solar system. It is also the largest planet in the solar system. The gravity of Jupiter on its surface is 2.4 times that of surface gravity of the Earth.
If a person weighs 100 pounds on the Earth then he would weigh 240 pounds on Jupiter.
Therefore, the correct answer is option (C), the meteor falls to Jupiter faster due to its greater gravitational force.
The complete question is missing, so i have attached the complete question.
Answer:
A) FBD is attached.
B) The condition that must be satisfied is for ω_min = √(g/r)
C) The tension in the string would be zero. This is because at the smallest frequency, the only radially inward force at that point is the weight(force of gravity).
Explanation:
A) I've attached the image of the free body diagram.
B) The formula for the net force is given as;
F_net = mv²/r
We know that angular velocity;ω = v/r
Thus;
F_net = mω²r
Now, the minimum downward force is the weight and so;
mg = m(ω_min)²r
m will cancel out to give;
g = (ω_min)²r
(ω_min)² = g/r
ω_min = √(g/r)
The condition that must be satisfied is for ω_min = √(g/r)
C) The tension in the string would be zero. This is because at the smallest frequency, the only radially inward force at that point is the weight(force of gravity).
