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Sholpan [36]
3 years ago
8

At a rock concert, the sound intensity 1.0 m in front of the bank of loudspeakers is 0.10 W/m2. A fan is 30 m from the loudspeak

ers. Her eardrums have a diameter of 8.4 mm. How much energy is transferred to each eardrum in 1.0 second?

Physics
1 answer:
aliina [53]3 years ago
5 0

Explanation:

Below is an attachment containing the solution.

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What holds the moon in place, orbiting around the Earth
AnnZ [28]

The Earth's gravity keeps the Moon orbiting us. It keeps changing the direction of the Moon's velocity. This means gravity makes the Moon accelerate all the time, even though its speed remains constant.

4 0
3 years ago
Which of these factors will increase the speed of a sound wave in air?
Artemon [7]
<h3>Answer;</h3>

-Temperature

<h3><u>Explanation;</u></h3>
  • Sound is a type of mechanical wave, which means it requires a material medium for transmission. It results from the vibration of particles.
  • The speed of sound in mediums varies depending on the property of the medium and a number of other factors which includes; temperature, pressure,  and humidity.
  • Temperature increases the speed of sound wave as particles at higher temperatures tend to possess more energy and thus they will vibrate faster and thus the sound wave will travel faster.
3 0
3 years ago
In a double slit experiment, 450 nm light passes through two slits producing an interference pattern where the first bright frin
musickatia [10]

Answer:

1.3 x 10⁻⁴ m

Explanation:

\lambda = wavelength of the light = 450 nm = 450 x 10⁻⁹ m

n = order of the bright fringe = 1

θ = angle = 0.2°

d = separation between the slits

For bright fringe, Using the equation

d Sinθ = n \lambda

Inserting the values

d Sin0.2° = (1) (450 x 10⁻⁹)

d (0.003491) = (450 x 10⁻⁹)

d = 1.3 x 10⁻⁴ m

6 0
3 years ago
Given a temperature of 300 Kelvin, what is the approximate temperature in degrees Celsius?
S_A_V [24]
<span>Jun 16, 2012 - Given a temperature of 300 Kelvin, what is the approximate temperature in degrees Celsius? –73°C 27°C 327°C 673°C.</span><span>
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3 0
4 years ago
Read 2 more answers
The captain of a boat wants to travel directly across a river that flows due exst with a speed of 100 m/sHe starts from the sout
Salsk061 [2.6K]

Answer:

86.51° North of West or 273.49°

Explanation:

Let V' = velocity of boat relative to the earth, v = velocity of boat relative to water and V = velocity of water.

Now, by vector addition V' = V + v'.

Since v' = 6.10 m/s in the north direction, v' = (6.10 m/s)j and V = 100 m/s in the east direction, V = (100 m/s)i. So that

V' = V + v'

V' =   (100 m/s)i + (6.10 m/s)j

So, we find the direction,Ф the boat must steer to from the components of V'.

So tanФ = 6.10 m/s ÷ 100 m/s

tanФ = 0.061

Ф = tan⁻¹(0.061) = 3.49°

So, the angle from the north is thus 90° - 3.49° = 86.51° North of West or 270° + 3.49° = 273.49°

7 0
3 years ago
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