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2 years ago

Suppose you start with 1.80 g of mgco3·5h2o, after complete dehydration how many grams of the sample do you have remaining?

1 answer:

5 0

The number of grams of the sample that remained after hydration is 0.87 grams

calculation
calculate the molar mass of MgCO3. 5 H2O which is

24 + 12+ (3 x16) + ( 5 x18) = 174 g/mol

we well know after hydration water evaporate leaving behind MgCO3
therefore the mass remained is for MgCO3

find the molar mass of MgCO3 = 24 +12 +( 3 x16) = 84 g/mol

the mass remained is therefore

= molar mass of MgCO3 / molar mass of MgCO3.5H2O x 1.80 g

= 84g/mol / 174 g/mol x1.8g = 0.87 grams

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2 years ago

Gasoline has a density of 0.749 g/mL. There are 454 grams in a pound and 3.7854 litres in a gallon. How many pounds does 19.2 ga

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Answer:

119.9 pound

Explanation:

Given data:

Density of gasoline = 0.749 g/mL

Volume of gasoline = 19.2 gal (19.2× 37854 =72679.9 mL)

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Solution:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

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3 years ago

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2 years ago

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What mass of HgO is required to produce 0.692 mol of O2? 2HgO(s) -> 2Hg(l) + O2(g)

Vika [28.1K]

The answer for the following problem is mentioned below.

Therefore 298.44 grams of mercuric oxide is needed to produce 0.692 moles of oxygen molecule

Explanation:

Given:

no of moles of the oxygen gas = 0.692

Also given:

2 HgO → 2 Hg + $O_{2}$

where,

HgO represents mercuric oxide

Hg represents mercury

$O_{2}$ represents oxygen

To calculate:

Molar mass of HgO:

Molar mass of HgO = 216 grams

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HgO = 200 +16 = 216 grams

We know;

2×216 grams of HgO → 1 mole of oxygen molecule

? → 0.692 moles of oxygen molecule

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= 298.944 grams of HgO

Therefore 298.44 grams of mercuric oxide is needed to produce 0.692 moles of oxygen molecule

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3 years ago

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fredd [130]

Answer:

Yes.

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Therefore, the equation will be reduced to:

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