To solve this problem we will consider the concepts related to the normal deformation on a surface, generated when the change in length is taken per unit of established length, that is, the division between the longitudinal fraction gained or lost, over the initial length. In general mode this normal deformation can be defined as

$\epsilon = \frac{\delta}{l} = \frac{l_0-l}{l}$

Here,

$\delta$ = Change in final length $(l_0)$ and the initial length $l$

PART A)

$\epsilon = \frac{\delta_1}{l}$

$\epsilon = \frac{l_0-l}{l_0}$

$\epsilon = \frac{1.02-1}{1}$

$\epsilon = 0.01961$

PART B)

$\epsilon = \frac{\delta_1}{l}$

$\epsilon = \frac{l_0-l}{l_0}$

$\epsilon = \frac{2-1.05}{2}$

$\epsilon = 0.475$

PART C)

$\epsilon = \frac{\delta_1}{l}$

$\epsilon = \frac{l_0-l}{l_0}$

$\epsilon = \frac{3.07-3}{3}$

$\epsilon = 0.0233$

Therefore the rank of this deformation would be B>C>A

7 0

3 years ago

Why does a rocket have such great momentum even if it is moving at a slow speed?

Artist 52 [7]

Answer:

Rockets provide a wonderful example of Momentum Conservation. As momentum in one direction is given to the rocket's exhaust gases, momentum in the other direction is given to the rocket itself.

Explanation:

First, think of two masses connected by a lightweight (massless!) compressed spring. When the two spring apart, conservation of momentum tells us the Center of Mass remains where it was (or moving as it was).

PTot,i = p1i + p2i = 0 + 0 = 0

PTot,f = p1f + p2f = PTot,i = 0

p1f + p2f = - m1 v1f + m2 v2f = 0

4 0

3 years ago

Read 2 more answers

How much money can be found in the pockets/purses of the 250 students in a class if no student may carry 2 identical banknotes w

vaieri [72.5K]

The minimum is $1- $5000000

5 0

3 years ago

PLEASE HELP - Your concept map will compare the manner in which energy is transferred by mechanical waves and electromagnetic wa