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Vilka [71]
2 years ago
7

Correct formula for tetrafluorine monoxide

Chemistry
1 answer:
salantis [7]2 years ago
5 0
F4OP2 I’m not sure if you were looking for the molecular formula or other formula
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Which electrophiles can react with an enol?
dlinn [17]

THE MOLECULE HAS A C=C AND AN -OH GROUP, SO IT IS CALLED AN ENE/OL, I.E., AN ENOL. ENOLS CAN BE FORMED ONLY FROM CARBONYL COMPOUNDS WHICH HAVE ALPHA HYDROGENS. THEY CAN BE FORMED BY ACID OR BASE CATALYSIS, AND ONCE FORMED ARE HIGHLY REACTIVE TOWARD ELECTROPHILES, LIKE BROMINE.

8 0
3 years ago
What is climate? How does it differ from weather
ozzi
Weather refers to short term atmospheric conditions while climate is the weather of a specific region averaged over a long period of time. Climate change refers to long-term changes.
6 0
3 years ago
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Fernanda looked at a sample of paint under a microscope. At right is the sketch she made of what she saw. Label A points to the
Degger [83]

Answer:dispersed state

dispersed medium

colloid

7 0
3 years ago
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When 150. g zinc sulfide are burned in excess oxygen, 68.5 g of zinc oxide are actually produced, along with sulfur dioxide. Det
Bumek [7]

%yield = 54.6%

<h3>Further explanation</h3>

Percent yield is the compare of the amount of product obtained from a reaction with the amount you calculated

(theoretical)

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

<h3 />

Reaction

2ZnS+3O₂ ⇒ 2ZnO+2SO₂

MW ZnS = 97.474 g/mol

  • mol ZnS

\tt \dfrac{150}{97.474}=1.54

MW ZnO = 81.38 g/mol

  • mol ZnO (from mol ZnS as limiting reactant, O₂ excess)

\tt \dfrac{2}{2}\times 1.54=1.54

  • Actual ZnO produced

\tt 1.54\times 81.38=125.33~g

Theoretical production = 125.388

  • %yield

\tt \dfrac{68.5}{125.33}\times 100\%=\boxed{\bold{54.6\%}}

4 0
3 years ago
How many molecules are present in 265 moles of CCl
Solnce55 [7]

Answer:

Option C. 1.60x10^26 molecules

Explanation:

Avogadro's hypothesis proved that that 1 mole of any substance contains 6.02x10^23 molecules.

From the above, we understood that 1 mole of CCl4 contains 6.02x10^23 molecules.

If 1 mole of CCl4 contains 6.02x10^23 molecules,

then, 265 moles of CCl4 will contain = 265 x 6.02x10^23 = 1.60x10^26 molecules

From the calculation made above, 265 moles of CCl4 contains 1.60x10^26 molecules.

5 0
3 years ago
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