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3 years ago

If 52500 J of heat is used to heat a 10200g block of metal and

Chemistry

1 answer:

Angelina_Jolie [31]3 years ago

5 0

Answer:

45.95 Jkg^-1°C^-1

Explanation:

as specific heat capacity = heat energy / mass × delta

temperature

=52500/10.2×112

=45.95 Jkg^-1°C^-1

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Find the density of a material, given that a 5.01 g sample occupies 3.46 mL

Alex73 [517]

Answer:

The answer is

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume}$

From the question

mass of material = 5.01 g

volume = 3.46 mL

The density of the material is

$density = \frac{5.01}{3.46} \\ = 1.44797687...$

We have the final answer as

Hope this helps you

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3 years ago

If the volume of an irregular sound is determined by the water displacement technique, its volume will be equal to

dolphi86 [110]

25 mL
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2 years ago

which gas law would you use to calculate the new pressure for a gas when the volume of the trapped gas changes while the tempera

meriva

Answer: Boyle's Law

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Boyle's Law is the pressure-volume law and it relates pressure and volume at constant temperature. Boyle's law states that pressure and volume vary inversely, meaning that as one goes up, the other one goes down.

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3 years ago

Read 2 more answers

Which formula represents the compound commonly known as phosphine

Arlecino [84]

I looked up what is the molecular formula for Phosphine and got this: PH3
Hope this helps! Let my know if this was correct.

8 0

3 years ago

Calculate the ratio of the mass ratio of SS to OO in SOSO to the mass ratio of SS to OO in SO2SO2. Consider a sample of SOSO in

Veronika [31]

Answer:

The ratio of the mass ratio of S to O; in SO, to the mass ratio of S to O; in SO₂, is 2:1

Explanation:

According to the consideration, let us first find the ratio of S and O in both the compounds

For SO:

$\frac{m_{S} }{m_{O} }= \frac{32}{16}\\\\ \frac{m_{S} }{m_{O} }= 2$

Let us express it as

$SO_{\frac{m_{S} }{m_{O} }} = 2$

For SO₂,

Due to two oxygen atoms in the molecule, the mass of oxygen will be taken two times

$\frac{m_{S} }{m_{O} }= \frac{32}{(2)(16)}\\\\ \frac{m_{S} }{m_{O} }= 1$

Let us express it as

$SO_2_{\frac{m_{S} }{m_{O} }}= 1$

Now, for the ratio of both the above-calculated ratios,

$\frac{SO_{\frac{m_{S} }{m_{O} }}}{SO_2_{\frac{m_{S} }{m_{O} }}}=\frac{2}{1}$

The required ratio is 2:1

3 0

3 years ago