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Step2247 [10]
3 years ago
5

If 52500 J of heat is used to heat a 10200g block of metal and

Chemistry
1 answer:
Angelina_Jolie [31]3 years ago
5 0

Answer:

45.95 Jkg^-1°C^-1

Explanation:

as specific heat capacity = heat energy / mass × delta

temperature

=52500/10.2×112

=45.95 Jkg^-1°C^-1

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A woman has a body mass of 53 kg. What is her mass in grams?
Alekssandra [29.7K]

Answer:

53000 grams

Explanation:

1kg to grams = 1000

therefore;

53 × 1000= 53000 grams

please rate brainliest

7 0
1 year ago
Read 2 more answers
Calculate the number of moles in 7g of nitrogen gas​
Andru [333]

Answer:

<h3>0.2498molN_{2}</h3>

Explanation:

7gN2 x \frac{1 mol}{2(14.01) g}

=0.2498mol N2

Nitrogen gas has the formula N_{2} so therefore that means you would have to multiply the mass in the molar by 2. To solve for the number of moles you need to cancel out the grams, you do this by using the molar mass of nitrgoen gas. You get the value on in the denominator from the periodic table (atomic mass of element). The grams will cancel out, leaving you with the number of moles when you divide 7/2(14.01).

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3 years ago
What is carbon sink and how it effects our environment?
Ronch [10]

Answer:

Explanation:

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5 0
2 years ago
Use standard enthalpies of formation to calculate ΔH∘rxn for the following reaction______.2H2S(g)+3O2(g)→2H2O(l)+2SO2(g) ΔH∘rxn
Ahat [919]

Answer:

-1,103.39KJ/mol

Explanation:

We use the subtract the standard enthalphies of formation of the reactants from that of the products. It must be taken into consideration that the enthalpy of formation of elements and their molecules alone are not taken into consideration. Hence, what we would be considering are the standard enthalpies of formation of H2S, H2O and SO2.

In places where we have more than one mole, we multiply by the number of moles as seen in the balanced chemical equations.

The standard enthalpies of the molecules above are as follows:

H2S = -20.63KJ/mol

H2O = -285.8KJ/mol

SO2 = -296.84KJ/mol

O2 = 0KJ/mol

ΔrH⦵ = [2ΔfH⦵(H2O) + 2 ΔfH⦵(SO2)] − [ΔfH⦵(H2S) + 3

 ΔfH⦵(O2)]

ΔrH⦵ =[(2 × -285.8) + (2 × -296.84)]

-[ 3 × -20.63)]

= (-571.6 - 593.68 + 61.89) = -1,103.39KJ/mol

6 0
3 years ago
A cell using protein-mediated facilitated diffusion is treated with a toxin that prevents conformation change in the membrane pr
seraphim [82]

Answer:

The most likely outcome is that carrier protein dysfunction will increase the gradient which will lead to disruption of cellular metabolism.

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