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algol [13]
2 years ago
6

A system gains 652 kJ of heat, resulting in a change in internal energy of the system equal to +241 kJ. How much work is done?

Chemistry
1 answer:
levacccp [35]2 years ago
3 0

Answer:

-411 kj

Explanation:

We solve by using this formula

∆U = ∆Q + ∆W

This formula is the first law of thermodynamics

Change in internal energy U = +241

Heat gained by system Q = 652

Putting the value into the equation

+241 = 652 + W

Workdone = 241 - 652

Workdone = -411 kj

Since work done is negative it means that work was done by the system

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AysviL [449]

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where, P is the pressure of the gas in atm.

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n is the no. of moles of the gas in mol.

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<em></em>

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<em></em>

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3 years ago
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