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patriot [66]
2 years ago
6

In the Fischer esterification reaction, a carboxylic acid reacts with an excess of alcohol in acidic conditions to form an ester

. During the reaction the sp2sp2 hybridized carbonyl carbon of the acid forms an sp3sp3 hybridized intermediate before returning to sp2sp2 hybridization in the product. Draw the structure of the neutral sp3sp3 hybridized intermediate and the ester product in the reaction between pentanoic acid and n‑propanol.
Chemistry
1 answer:
Paul [167]2 years ago
4 0

Answer:

See explanation and image attached

Explanation:

Esterification is a reaction of an alkanol and an alkanoic acid to yield an ester and water as products. It is analogous to inorganic neutralization reaction.

The process may be acid catalyzed. As mentioned in the question, the process of ester formation between pentanoic acid and n‑propanol first involves the carbonyl in going through an sp3 hybridized intermediate before returning to sp2 hybridized state in the product.

The image of the neutral form of this intermediate as well as the final structure of the ester are both shown in the image attached to this answer.

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Total pressure: 2.89 atm

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Explanation:

We should apply the Ideal Gases Law to solve this:

P . V = n . R . T

We need n, which is the total moles for the mixture

Total moles = Moles of CO + Moles of ClF₅

Moles of CO = mass of CO / molar mass CO → 18 g/28 g/mol = 0.643 mol

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0.643 mol + 0.0812 mol → 0.724 moles in the mixture

So we have the total moles so with the formula we would know the total pressure.

P . 6L = 0.724 mol . 0.082L.atm/mol.K . 292.2K

P = ( 0.724 mol . 0.082L.atm/mol.K . 292.2K) / 6L

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Moles of gas X /Total moles = Partial pressure of gas X/Total pressure

(Moles of gas X / Total moles) . Total pressure = Partial pressure of gas X

Mole fraction CO = 0.643 / 0.724 = 0.88

Partial pressure CO = 0.88 . 2.89 atm → 2.56 atm

Mole fraction ClF₅ = 0.0812 / 0.724 = 0.12

Partial pressure ClF₅ = 0.12 . 2.89 atm → 0.33 atm

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3 years ago
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