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3 years ago

Find the 3rd term in the expansion of (a+b)^8 in simplest form.

Mathematics

1 answer:

Art [367]3 years ago

4 0

Answer:

The fifth term is the middle term of nine, with coefficient given by all the ways of choosing 4 items out of 8 , namely the ways of choosing 4 a 's out of 8 binomial factors.

Step-by-step explanation:

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All the people of a neighborhood pooled together and won the lottery they won 10,000,000 and each person got a 0.02 share. How m

natka813 [3]

Answer:

500000000

Step-by-step explanation:

10000000 ÷ 0.02

4 0

2 years ago

The sum of the first 12 terms of a geometric sequence with 10 as the first term and a common ratio of 0.3 is __________.

BaLLatris [955]

Answer: 14.2638366937

Step-by-step explanation:

A geometric sequence is a sequence in which each term is multiplied by a number, called the common ratio, to get the next term.

So, if the first term of the geometric sequence is 10 and the common ratio is 0.3, the sequence would be 10, 0.3(10), 0.3 x 0.3 x 10... and so forth. This becomes:

10, 3, 0.9, 0.27, 0.081, 0.00243, 0.00729, 0.002187, 0.0006561, 0.00019683, 0.000059049, 0.0000177147...

You add these first 12 terms to get 14.2638366937.

7 0

3 years ago

10x^2-35x=?<br><br> Factor out the greatest common factor

Leona [35]

10x^2 - 35x....the GCF is 5x

5x(2x - 7) <==

6 0

3 years ago

Describe the relationship between the values of the digits in 9,999,999

NARA [144]

Starting on the far right, ones, tens, hundreds, thousands, ten thousands, hundred thousands and millions.

6 0

2 years ago

The radii of two circles are in the ratio of 3 to 1. Find the area of the smaller circle if the area of the larger circle is 27

Naddik [55]

ANSWER
$3\pi sq.\: in.$

EXPLANATION

Let R be the radius of the bigger circle and r, be the radius of the smaller circle.

Then their ratio is given as,

$R:r=3:1$

We can rewrite it as fractions to get,

$\frac{R}{r} = \frac{3}{1}$

We make R the subject to get,

$R = 3r$

The area of the bigger circle can be found using the formula,

$Area=\pi {r}^{2}$

This implies that,

$Area=\pi ({3r})^{2}$

$Area=9\pi {r}^{2}$

But it was given in the question that, the area of the bigger circle is 27π.

$27\pi=9\pi {r}^{2}$

We divide through by 9π to get,

$3 = {r}^{2}$

This means that,
$r = \sqrt{3}$

The area of the smaller circle is therefore

$= \pi {( \sqrt{3}) }^{2}$

$= 3\pi$

8 0

3 years ago

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