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Alina [70]
3 years ago
15

You and two friends are planning a vacation. You want to keep the cost below $120 per person. Write and solve an inequality that

represents
the total cost of the vacation
Mathematics
1 answer:
Strike441 [17]3 years ago
4 0

Answer:

Inequality is y < 360

Step-by-step explanation:

Let y be the total cost of the vacation.

Now, since there are 3 persons in consideration and we want to keep the cost below $120 per person. Therefore, cost for each person is; y/3

Thus,representing this in inequality gives;

y/3 < 120

Multiplying both sides by 3 to get;

y < 360

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two weeks ago i bought 2 cupcakes last week i bought 7 today id like to follow this pattern how many cupcakes do i want
monitta

Answer:

12

Step-by-step explanation:

2+5=7

7+5=12

Pattern of +5

5 0
3 years ago
Read 2 more answers
A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute
nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

P(k\geq8)=1-P(k

P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\

P(k

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002

5 0
3 years ago
What happens when a triangle is dilated using one of the vertices as the center of the dilation? Complete
Yuki888 [10]

Answer:

The sides of the triangles adjacent to the center of dilation will be collinear. The third sides of the pre-

image and image will be “parallel”

The vertex used as the center of dilation will be in “the same location in both triangles”

8 0
3 years ago
Need help with this.
skelet666 [1.2K]

Answer:

-5/2(3x+4)<6-3x (multiply with -5/2)

-15/2x-10<6-3x (multiply with 2)

-15x-20<12-6x (change sides)

-15x+6x<12+20

-9x<12+20

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x>-32/9

Hope this will help u :)

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3 years ago
True or false<br><br> A rhombus is an isosceles trapezoid
Elina [12.6K]

Answer:

false

Step-by-step explanation:

7 0
2 years ago
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