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3 years ago

The of a wave is the density of the medium’s particles at the compression of the wave.

Physics

2 answers:

Westkost [7]3 years ago

7 0

'Amplitude' is the correct answer i just took the quiz

andrew11 [14]3 years ago

6 0

<span>Amplitude is the correct answer. I hope this helps.</span>

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A 26.0 kg beam is attached to a wall with a hinge while its far end is supported by a cable such that the beam is horizontal. If

Nuetrik [128]

Answer:

Force exerted by the hinge on the beam = 109.24N

Explanation:

Weight = mg = 26 x 9.81 = 255.06 N

Vertical component = T sin θ

Horizontal component = Tcos θ

Now, there are 3 vertical forces acting on the beam. These are;

- The downward force which is the weight of the beam.

- The vertical components of the tension in the cable.

-The force that hinge exerts on the beam are the upward forces.

Hence, for the beam to remain horizontal, the sum of the upward forces must be equal to the weight of the beam.

For us to determine the vertical component of the tension in the cable, we will do a torque problem. Let the pivot point be at the hinge. Let’s assume that the length of the beam is L. The vertical component of the tension in the cable will produce clockwise torque while the weight of the beam will produce counter clockwise torque.

Tbus;

Clockwise torque = TL sin 61

Since the center of mass of beam is at the middle of the beam, the distance from the hinge to the weight of the beam is L/2.

Counter clockwise torque = WL/2

Thus;

TL sin 61 = WL/2

L will cancel out.

T sin 61 = 255.06/2

T x 0.8746 = 127.53

T = 127.53/0.8746 = 145.82 N

Now, the equation to determine the vertical component of the force that the hinge exerts on the beam is given as;

T + F = W

Thus;

145.82 + F = 255.06

F = 255.06 - 145.82 = 109.24 N

8 0

3 years ago

Picture a long, straight corridor running east-west, with a water fountain located somewhere along it. Starting from the west en

Brut [27]

Answer:

The corridor's distance is "90 m".

Explanation:

She heads in the east directions but creates the first pause, meaning she crosses the distance 'x' in step 1.
Now, provided that perhaps the distance by her to another fountain or waterfall just after the first stop is twice as far away she traveled.
Because she moved the distance of 'x,' then, therefore, her distance towards the fountain of '2x.' She casually strolls and once again pauses 60 m beyond her stop.
The gap about her to the waterfall during that time approximately twice the distance and her to the eastern end of the hallway.
Assume her gap from either the east end of the platform seems to be 'y' at either the second stop, after which '2y' may become the distance between the 2nd pause and the waterfall.

Now,

⇒ $2x + 2y = 60$

⇒ $x + y = 30$

The total distance of the corridor will be:

= $x + 2x + 2y + y$

= $3\times (x + y)$

= $3\times 30$

= $90 \ m$

4 0

3 years ago

Your friend asks you for a glass of water and you bring her 5 milliliters of water. Is this more or less than what she was proba

Eddi Din [679]

Probably not what you were expecting... the average bottle of water is 24 ounces. 5 milliliters is about the amount of water in a spoon. Hope this helps!!!

3 0

3 years ago

What force is acting on the rainwater in the model?

Vikki [24]

The force is gravitational because when something is falling is call gravitational

8 0

3 years ago

Read 2 more answers

A penny is dropped from the top of a building that is 300.0 m tall. Calculate the speed of the penny as it hits the ground. (met

Sauron [17]

We have the equation of motion $s = ut + \frac{1}{2} at^2$ , where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.

Here s = 300 m, u = 0 m/s, a = 9.81 $m/s^2$

Substituting

$300 = 0*t+\frac{1}{2} *9.8*t^2\\ \\ 4.9t^2 = 300\\ \\ t =7.82 seconds$

Now we have v = u+at, where v is the final velocity

Here u = 0 m/s, a= 9.81 $m/s^2$ and t = 7.82 seconds

Substituting

v = 0+9.8*7.82 = 76.68 m/s

The speed with which the penny strikes the ground = 76.68 m/s.

3 0

3 years ago