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3 years ago

What force is required to give an object with mass 300 kg an acceleration of 2

Physics

1 answer:

Andre45 [30]3 years ago

5 0

Answer:

C. 600 N

Explanation:

Given,

mass of object (m)= 300kg

acceleration(a) =2m/s^2

We know that,

Force(F)=ma

=300*2

=600N

So,600N force is required to give an object.

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An object is attached to a vertical spring and bobs up and down between points A and B. Where is the object located when its kin

gtnhenbr [62]

Answer:

a. at either A or B

Explanation:

Kinetic energy may be defined as the energy of the system or an object which is due to its velocity of the object it possess.

In the context, an object having mass is attached to spring which is vertical and the object moves up and down due to spring effect between points A and B. Now these points A and B are the extreme points after which the object bounces back.

At point A and B, the velocity of the object becomes zero and hence the kinetic energy of a body varies directly proportional to its velocity.

i.e. Kinetic energy $= \frac{1}{2} \text{mass} \times (\text{ velocity})^2$

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3 years ago

What is weight in Newton’s, of a 50.-kg person on earth

Svetlanka [38]

Answer:

It is about 490 Newtons. 490.3325 to be exact

Explanation:

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3 years ago

Which statement is an example of the law of conservation of energy

WITCHER [35]

Answer:

The law of conservation of energy can be seen in these everyday examples of energy transference: Water can produce electricity. Water falls from the sky, converting potential energy to kinetic energy. This energy is then used to rotate the turbine of a generator to produce electricity.

Explanation:

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3 years ago

A force of 6600 N is exerted on a piston that has an area of 0.010 m2

sveticcg [70]

Answer:

Choice A: approximately $0.015\; \rm m^2$ , assuming that the two pistons are connected via some confined liquid to form a simple machine.

Explanation:

Assume that the two pistons are connected via some liquid that is confined. Pressure from the first piston:

$\displaystyle P_1 = \frac{F_1}{A_1} = \frac{6.600\times 10^3\; \rm N}{1.0\times 10^{-2}\; \rm m^{2}} = 6.6\times 10^{5}\; \rm N \cdot m^{-2}$ .

By Pascal's Principle, because the first piston exerted a pressure of $6.6\times 10^{5}\; \rm N \cdot m^{-2}$ on the liquid, the liquid will now exert the same amount of pressure on the walls of the container.

Assume that the second piston is part of that wall. The pressure on the second piston will also be $6.6\times 10^{5}\; \rm N \cdot m^{-2}$ . In other words:

$P_2 = P_1 = 6.6\times 10^{5}\; \rm N \cdot m^{-2}$ .