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ki77a [65]
2 years ago
12

Michelle and her friends wondered who had the most pop albums in their music collection. She recorded the information below: Mus

ic Collection Survey Name Number of Pop Albums Total Number of Albums in the collection Michelle 33 60 Sasha 36 78 Kat 40 89 Monica 24 59 Based on the survey, which friend had the greatest percentage of pop albums?
Mathematics
1 answer:
Ira Lisetskai [31]2 years ago
8 0

Answer:

Michelle

Step-by-step explanation:

Given the data:

S Name No of Pop Albums Total No of Albums Michelle 33 60

Sasha 36 78

Kat 40 89

Monica 24 59

Percentage of pop Albums:

(Number of pop album / total number of albums) * 100%

Michelle :

(33 /60) * 100% = 55%

Shasha:

(36 /78) * 100% = 46.15%

Kat:

(40 / 89) * 100% = 44.94%

Monica :

(24 / 59) * 100% = 40.67%

Hence, Michelle has the greatest percentage of pop Albums

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\bold{\huge{\pink{\underline{ Solution }}}}

\bold{\underline{ Given }}

  • <u>We </u><u>have </u><u>given </u><u>two </u><u>linear </u><u>equations </u><u>that</u><u> </u><u>is </u><u>2x </u><u>-</u><u> </u><u>3y </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>and </u><u>x</u><u> </u><u>+</u><u> </u><u>3y </u><u>=</u><u> </u><u>1</u><u>2</u><u> </u><u>.</u>

\bold{\underline{ To \: Find }}

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>x </u><u>and </u><u>y </u><u>by </u><u>elimination </u><u>method</u><u>. </u>

\bold{\underline{ Let's \: Begin }}

\sf{ 2x - 3y = -6 ...eq(1)}

\sf{ x +  3y = 12 ...eq(2)}

<u>Multiply </u><u>eq(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>by </u><u>2</u><u> </u><u>:</u><u>-</u>

\sf{ 2( x + 3y = 12 )}

\sf{ 2x + 6y = 24 }

<u>Subtract </u><u>eq(</u><u>1</u><u>)</u><u> </u><u>from </u><u>eq(</u><u>2</u><u>)</u><u> </u><u>:</u><u>-</u>

\sf{ 2x + 6y -( 2x - 3y) = 24 -(-6)}

\sf{ 2x + 6y - 2x + 3y = 24 + 6 }

\sf{   9y = 30 }

\sf{   y = 30/9}

\sf{\red{ y = 10/3}}

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\sf{ 2x - 3(10/3) = -6 }

\sf{ 2x - 10 = -6 }

\sf{ 2x  = -6 + 10}

\sf{ x  = 4/2}

\sf{\red{ x  = 2}}

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