(f○g)(x)=f(g(x))
(f○g)(x)=6(4x+1)
(f○g)(x)=24x+6
You need to find a common factor that both the
numerator
and denominator have. 16 and 12 have common divisible factors of 2 and 4(excluding 1, because 1 is self-defined but doesn't simplify values at all).
We use the highest factor, in this case, 4.
Divide 16 by 4 and 12 by 4.
16/4 = 4
12/4 = 3
We put 4 in place of the numerator and 3 in place of the denominator.
Answer:
the solution of the system is:
x = 1 and y = 2.
Step-by-step explanation:
I suppose that we want to solve the equation:
-6*x + 6*y = 6
6*x + 3*y = 12
To solve this, we first need to isolate one of the variables in one of the equations.
Let's isolate y in the first equation:
6*y = 6 + 6*x
y = (6 + 6*x)/6
y = 6/6 + (6*x)/6
y = 1 + x
Now we can replace this in the other equation:
6*x + 3*(1 + x) = 12
6*x + 3 + 3*x = 12
9*x + 3 = 12
9*x = 12 - 3 = 9
x = 9/9 = 1
Now that we know that x = 1, we can replace this in the equation "y = 1 + x" to find the value of y.
y = 1 + (1) = 2
Then the solution of the system is:
x = 1 and y = 2.
2 divided by 18 is 9 and 3 divided by 18 is 6 hope that helps