HELP ME ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!

All help is needed, thanks

yarga [219]

Answer:

smoke
marshmallow
paint
Body spray

Explaination:

Firstly, what are colloids?

Colloids are a mixture of two substances:

one of those substances are insoluble and inseparable

There are 4 types of colloids:

Sol- Solid in a liquid
Emulsion- Liquid in a liquid
Foam- Gas in solid/liquid
Aerosol- Solid/liquid in gas

So on to the answers:

Smoke consists of solid and gas and since the solid is being carried by the gas, it is a solid in a gas (aerosol)
Marshmellow consists of tiny air bubbles and sugar(solid), the air bubbles is inside the solid making it a gas in a solid (foam)
Body spray turns gas into liquid after spraying it through the can, making it a liquid in a gas (aerosol)
Paint dries up to become solid which makes it a solid is a liquid (sol)

Hope y'all understand

3 0

3 years ago

In the presence of oxygen, the three-carbon compound pyruvate can be catabolized in the citric acid cycle. First, however, the p

Flura [38]

Answer:1.

Explanation: This reaction is catalyzes by pyruvate dehydrogenase. Pyruvate being the end product of glycolysis has many fates after glycolysis,one of which is to enter the TCA(Tricarboxylic acid cycle) cycle. It is first converted to actetate by the action of pyruvate dehydrogenase. This enzyme converts pyruvate to acetate releasing CO2 and NADH because this oxidative decarboxylation of pyruvate is coupled with reduction of NAD+ which can feed into the electron transport chain.

6 0

3 years ago

What are some differences between mixtures and compounds?

BlackZzzverrR [31]

One is a mixture and the other is a compound

8 0

3 years ago

Which units express specific heat capacity?

mixer [17]

Answer : The correct option is $\frac{J}{g^oC},\frac{J}{gK},\frac{cal}{g^oC},\frac{cal}{gK}$ .

Explanation :

Specific heat capacity : It is defined as the amount of heat required to raise the temperature of one gram of substance by one degree Celsius.

Formula used :

$q=mc\Delta T\\c=\frac{q}{m\Delta T}$

where,

q = heat required

m = Mass

c = specific heat capacity

$\Delta T$ = change in temperature

The unit of heat are expressed in terms of Joules, calories.

The unit of temperature are expressed in terms of degree Celsius, kelvin.

It is expressed as $\frac{J}{g^oC},\frac{J}{gK},\frac{cal}{g^oC},\frac{cal}{gK}$ .

5 0

3 years ago

Read 2 more answers

Given the following: [G3P] = 1.5x10-5M; [BPG] = 3.0x10-3M ; [NAD+] = 1.2x10-5M; [NADH]=1.0x10-4 ; [HPO42-]= 1.2x10-5 M; pH = 7.5

mel-nik [20]

<u>Answer:</u> The given reaction is non-spontaneous in nature.

<u>Explanation:</u>

To calculate the $H^+$ concentration, we use the equation:

$pH=-\log[H^+]$

We are given:

pH of the solution = 7.5

$7.5=-\log [H^+]$

$[H^+]=10^{-7.5)=3.1\times 10^{-8}M$

For the given chemical equation:

$\text{Glyceraldehyde3-phosphate }+NAD^++HPO_4^{2-}\rightarrow \text{1,3-Biphosphoglycerate }+NADH+H^+$

The equation used to Gibbs free energy of the reaction follows:

$\Delta G=\Delta G^o+RT\ln K_{eq}$

where,

$\Delta G$ = free energy of the reaction

$\Delta G^o$ = standard Gibbs free energy = 6.3 kJ/mol = 6300 J/mol (Conversion factor: 1kJ = 1000J)

R = Gas constant = 8.314J/K mol

T = Temperature = $25^oC=[273+25]K=298K$

$K_{eq}$ = Ratio of concentration of products and reactants = $\frac{[BPG][NaDH][H^+]}{[G_3P][NAD^+][HPO_4^{2-}]}$

$[BPG]=3.0\times 10^{-3}M$

$[NADH]=1.0\times 10^{-4}M$

$[H^+]=3.1\times 10^{-8}M$

$[G_3P]=1.5\times 10^{-5}M$

$[NAD^+]=1.2\times 10^{-5}M$

$[HPO_4^{2-}]=1.2\times 10^{-5}M$

Putting values in above equation, we get:

$\Delta G=6300J/mol+(8.314J/K.mol\times 298K\times \ln (\frac{(3.0\times 10^{-3})\times (1.0\times 10^{-4})\times (3.1\times 10^{-8})}{(1.5\times 10^{-5})\times (1.2\times 10^{-5})\times (1.2\times 10^{-5})}))\\\\\Delta G=9917.02J/mol=9.92kJ/mol$

For the reaction to be spontaneous, the Gibbs free energy of the reaction must come out to be negative.

As, the Gibbs free energy of the reaction is positive. The reaction is said to be non-spontaneous.

Hence, the given reaction is non-spontaneous in nature.

4 0

3 years ago