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irga5000 [103]
2 years ago
9

How many moles are in 75 grams of potassium

Chemistry
2 answers:
slamgirl [31]2 years ago
7 0

Answer:

what?

Explanation: huh?

LiRa [457]2 years ago
7 0

Answer:

2

Explanation:

ughhhhhhh this shoud be long

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If 12.5 grams of the original sample of cesium-137 remained after 90.6 years, what was the mass of the original sample?
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Answer:

Mass of original sample = 100 g

Explanation:

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k=\frac{\ln2}{30.17}\ year^{-1}

The rate constant, k = 0.02297 year⁻¹

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Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

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Applying in the above equation, we get that:-

12.5\ g=[A_0]e^{-0.02297\times 90.6}

[A_0]=\frac{12.5}{e^{-0.02297\times 90.6}}\ g=100\ g

<u>Mass of original sample = 100 g</u>

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