1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Drupady [299]
3 years ago
6

Abcdefghijklmnopqrstuvwxyz

Chemistry
2 answers:
Sholpan [36]3 years ago
8 0

now I know my abcs next time wont you sing with me

wel3 years ago
7 0

Answer:

12345678910

Explanation:

You might be interested in
If 2.0 moles of A and 3.0 moles of B react according to the hypothetical reaction below, how many moles of the excess reactant w
valina [46]
.5 mol of A will be left over since 1.5 mol of A will be used for every 3 mol of B due to the 2:1 ratio established by the formula.
5 0
3 years ago
Read 2 more answers
Are these answers correct? I’m a little unsure
Naily [24]

Answer:

yes I think that they are correct

8 0
3 years ago
An electron:
Korvikt [17]
It has a negative charge emits energy when it moves to a lower energy orbit from an excited state and it has the same mass as a proton
4 0
3 years ago
In a parallel circuit, there is only one path for current to take.<br> true or false
OlgaM077 [116]
The answer is true!!!!!!!!!!!!!!!!!!!!!!!
6 0
3 years ago
Read 2 more answers
28) Consider a 21.0 mL sample of pure lemon juice with a citric acid (H3C6H5O7) concentration of 0.30M. a. How many moles of cir
Damm [24]
<h3>#a. Answer:</h3>

0.0063 mole

<h3>Solution and explanation:</h3>

We are given 21.0 mL citric acid with a concentration of 0.30 M

Part a requires we calculate the number of moles of citric acid.

We need to know how to calculate the concentration of a solution;

Concentration or molarity = Number of moles ÷ Volume of the solution

Thus;

Number of moles = Concentration × Volume

Hence;

Moles = 0.30 M × 0.021 L

         = 0.0063 mole

<h3>#b. Answer</h3>

1.21 g citric acid

<h3>Solution</h3>

Part B

We are required to calculate the mass of citric acid in the sample

Number of moles of a compound is calculated by dividing its mass by its molar mass.

Molar mass of Citric acid = 192.124 g/mol

Moles of citric acid = 0.0063 mole

But; Mass = Number of moles × Molar mass

Mass of citric acid = 0.0063 mol × 192.124 g/mol

                             = 1.21 g citric acid

<h3>#c. Answer</h3>

4.167 mL

<h3>Solution:</h3>

Part C

We are required to determine the initial volume before dilution;

We have;

Initial concentration (M1) = 0.30 M

Final volume (V2) = 250 mL or 0.25 L

Final concentration (M2) = 0.0050 M

Using the dilution formula we can get the initial volume;

Therefore, since; M1V1 =M2V2

V1 = M2V2÷M1

   = (0.0050 × 0.25)÷ 0.30

   = 0.004167 L or

   = 4.167 mL

Therefore, the initial volume of the solution is 4.167 mL

8 0
3 years ago
Other questions:
  • How much of the excess reactant remains after the reaction?
    13·2 answers
  • _Cuo +H, → _Cu + _H,0
    15·1 answer
  • A sample of oxygen is collected over water at a total pressure of 692.2 mmHg at 17°C. The vapor pressure of water at 17°C is 14.
    15·1 answer
  • When 0.50 L of a 12 M solution is diluted to 1.0 L, what is the resulting molarity?
    14·1 answer
  • The diagram is a model of one way that materials move into a cell.
    7·2 answers
  • What does purified water and fluorine make?
    12·1 answer
  • The chemical formula for an emerald is Be3Al2(SiO3)6. An emerald can be described as
    12·2 answers
  • How many moles of N20 gas would have a volume of 3.8 L at 460 mmHg and 77°C?
    10·1 answer
  • What is the density of a solid with a mass of 75g and a volume of 5 cm^3?​
    5·1 answer
  • According to VSEPR Theory, the molecular geometry for CH3+ is
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!