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Katarina [22]
3 years ago
10

if a sample of oxygen gas occupies a volume of 2.15 At a pressure of 0.572 atm and a temperature of 25 c what volume would this

sample occupy at STP
Chemistry
1 answer:
MaRussiya [10]3 years ago
8 0
Answer:
            1.126 L

Solution:

Let's assume the gas is behaving ideally, then initial and final states of given gas are given as,

                                      P₁ V₁ / T₁  =  P₂ V₂ / T₂   ---- (1)
Data Given;

                  P₁  =  0.572 atm

                  V₁  =  2.15 L

                  T₁  =  25 °C + 273  =  298 K

                  P₁  =  1.00 atm

                  V₂  =  ?

                  T₂  =  0 °C + 273  =  273 K

Solving equation 1 for V₂,

                 V₂  =  P₁ V₁ T₂ / T₁ P₂

Putting Values,

                 V₂  =  (0.572 atm × 2.15 L × 273 K) ÷ (298 K × 1 atm)

                 V₂  =  1.126 L
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navik [9.2K]
We can solve this problem by using Henry's law. 
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</span>We can calculate the constant from the first piece of information and then use Henry's law to calculate solubility in open drink.
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C_o=kP_o&#10;
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4 0
3 years ago
Why do things dissolve so well in water ?
Goshia [24]

Answer:

Explanation:

Water is called the universal solvent. It is a polar molecule (105 degree angle between the H atoms)   that gives it a + and a - side so to speak....which allows it to 'pull apart'  substances....overcome their intra-molecular attractions to each other ...i.e. disssovle them

4 0
3 years ago
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neonofarm [45]
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3 years ago
1. A chemist prepares hydrogen fluoride by means of the following reaction:
Natasha_Volkova [10]

Answer:

a) <em>Theoretical Yield of HF = 5.64 grams</em>

b) <em>Percentage Yield = 39%</em>

Explanation:

Reaction Given:

CaF2 + H2SO4 -> CaSO4 + 2HF

CaF2 = 11g

H2SO4 = Used in excess

HF = 2.2 g production = Actual Yield

So, Let's write down the molar masses:

Molar Mass of CaF2 = 78 g /mol

Molar Mass of HF = 20 g/mol

From the reaction, we can see the 1 mole of CaF2 gives the 2 moles of HF

i.e

a) Theoretical Yield of HF:

1 mole CaF2 = 2 moles HF

78 g CaF2 = 2 x 20 g of HF

78 g CaF2 = 40 g of HF

1 g CaF2 = 40g/78g of HF

And in the question it is given that chemist used 11 g of CaF2 so,

1 x 11 g of CaF2 = 11 x 40/78 g of HF

11 g of CaF2 = 440/78 g of HF

11 g of CaF2 = 5.64 g of HF

And this is the theoretical yield

<em>Theoretical Yield of HF = 5.64 grams</em>

b) Now, calculate the Percentage Yield of HF

<em>Percentage Yield = Actual Yield /Theoretical Yield x 100</em>

Percentage Yield = 2.2 g /5.64 g x 100

Percentage Yield = 39%

8 0
3 years ago
What volume (in liters) does 2.895 moles of oxygen occupy at stp?
LekaFEV [45]

Answer:

64.9 L

Explanation:

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5 0
3 years ago
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