In the following reaction, how many grams of oxygen will react with 10.47 grams of benzene (C6H6)? 2C6H6 + 1502 12CO2 + 6H2O The
molar mass of benzene is 78.1074 grams and that of O2 is 32 grams.
1 answer:
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Considering the ideal gas law, the pressure of the gas sample is 122.18 atm.
<h3>What is an ideal gas</h3>An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
<h3>Definition of ideal gas law</h3>An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of gases:
P×V = n×R×T
<h3>Pressure of the gas sample</h3>In this case, you know:
- P= ?
- V= 500 mL= 0.5 L
- n= 2.50 moles
- R= 0.082
- T= 25 °C= 298 K
Replacing in the ideal gas law:
P×0.5 L = 2.50 moles ×0.082 ×298 K
Solving:
P= (2.50 moles ×0.082 ×298 K)÷ 0.5 L
<u><em>P= 122.18 atm</em></u>
Finally, the pressure of the gas sample is 122.18 atm.
Learn more about the ideal gas law:
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