Answer:
1683.6J
Explanation:
Given:
n= no. Of mol= 2.70 mol
T= Temperature= 30.0 K
Q= n Cv × ∆T .........eqn(1)
Where CV= molar heat capacity=5/2R for diatomic particle ,such as H2
CV= molar heat capacity=3/2R for diatomic, such as H
R= gas constant= 8.314 J/mol.K
Q= heat energy
For a diatomic molecules
Q= n Cv × T
But
Cv= molar heat capacity=5/2R = 5/2(8.314)=20.785
CV= 20.785
. ∆T= Temperature= 30.0 K
Then substitute the values into the eqn(1)
Q= 2.70 × 5/2(8.314) × 30
Q= 2.70 × 20.785 × 30
=1683.6J
