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3 years ago

Given that angle one is congruent to angle to how do you prove that P is parallel to Q

Mathematics

1 answer:

Sonbull [250]3 years ago

3 0

Answer:

assemble the proof by dragging tiles to the statements and reasons columns.

angles: ~= , <1 , <2 , <3,

lines: | | , p , q ,

statements: <1 and <3 are vertical reasons: given , transitive property , vertical angles theorem , def. of vertical

Step-by-step explanation:

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4+2i+-6-7i may you tell.me the answer please stuck on this

PtichkaEL [24]

$Grouping \ factors:\\\\
Similar\ factors\ are:\\
4-6=-2\ \ \ \ and\ \ \ \ 2i-7i=-5i\\\\
Solution\ is\ -5i-2.
$

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4 years ago

Read 2 more answers

Why will i be a good role model essay please i need help this is due tomorrow

WITCHER [35]

Answer:

Relate the points down below to yourself and give examples

Step-by-step explanation:

You show confidence and leadership

Being yourself/unique

You speak and interact kindly with everyone

You show respect and concern for others

You give advice to those who need it

You have humility and a willingness to admit mistakes.

You do good things outside of school

7 0

3 years ago

Two workers, a trainer and a trainee, working together can do a job in 3 hours. The trainer is 3 times faster than the trainee t

Flauer [41]

Answer:

4 hours

Step-by-step explanation:

Ratio of working together

Job : number of hours

1 : 3 = 1/3

Trainer

Job : number of hours

1 : x = 1/x

Trainee

Job : number of hours

1 : 3x = 1/3x

1/x + 1/3x = 1/3

Multiply through by 3x

3x(1/x) + 3x(1/3x) = 3x(1/3)

3 + 1 = x

4 = x

x = 4 hours

It takes the trainee 4 hours to finish the job

4 0

3 years ago

Identify the expression that is equivalent by distributive property of

Evgen [1.6K]

C is the right answer

8 0

3 years ago

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

Naddika [18.5K]

Answer:

The rocket will hit the ground after about 8.20 seconds.

Step-by-step explanation:

The height of the rocket y, in feet, x seconds after launch is modeled by the equation:

$y=-16x^2+121x+83$

We want to find the time at which the rocket will hit the ground.

If it hits the ground, the height of the rocket y will be 0. Thus:

$0=-16x^2+121x+83$

We can solve for x. Factoring (if possible at all) or completing the square can be tedious, so we can use the quadratic formula:

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

In this case, a = -16, b = 121, and c = 83. Substitute:

$\displaystyle x=\frac{-(121)\pm\sqrt{(121)^2-4(-16)(83)}}{2(-16)}$

Simplify:

$\displaystyle x=\frac{-121\pm\sqrt{19953}}{-32}$

Divide everything by -1 and simplify the square root. The plus/minus will remain unchanged:

$\displaystyle x=\frac{121\pm3\sqrt{2217}}{32}$

Therefore, our two solutions are:

$\displaystyle x=\frac{121+3\sqrt{2217}}{32}\approx 8.20\text{ or } x=\frac{121-3\sqrt{2217}}{32}\approx -0.63$

Since time cannot be negative, we can ignore the second solution.

Therefore, the rocket will hit the ground after about 8.20 seconds.

7 0

3 years ago