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Jobisdone [24]
3 years ago
10

Plsss helppppppppp pls help me

Mathematics
2 answers:
scoray [572]3 years ago
8 0
What are your questions?
pychu [463]3 years ago
4 0

Answer: should be B if im wrong sorry :(

Step-by-step explanation:

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the length of a rectangle is 2 cm less than 7 times the width.the perimeter is 60 cm. find the width and length
Mnenie [13.5K]
Width = 4
length = 26
5 0
3 years ago
Read 2 more answers
13. A high school has 1600 students. In a random sample of 50 students, 15
Orlov [11]

Answer:

480

Step-by-step explanation:

In 50 student's play station is owned by       =15 student's

∴ In 1 student play station is owned by         =15÷50 student

∴In 1600 student's play station is owned by =(1600×15)÷50 student's

                                                                         =480 student's

∴The number of the student at the high school who

own a Play station is 480

                                     (Ans)

3 0
3 years ago
What is the least common denominator of the fraction 4 over x plus the fraction 2 x over x minus 1 plus the fraction x plus 3 ov
Leya [2.2K]

If we consider x having any other value then 0,1 or 2 then the answer is b.2x(x-1)

8 0
3 years ago
00:57
prisoha [69]
<h3>Given:</h3>
  • h= 19 ft
  • r= 12 ft
<h3>Note that:</h3>
  • h= Height
  • r= Radius
<h3>To find:</h3>

The volume of the given cone.

<h3>Solution:</h3>

\large\boxed{Formula:V= \frac{1}{3}\pi{r}^{2}h}

\large\boxed{\red \pi \red = \red 3 \red . \red 1 \red 4}

Let's solve!

Substitute the values according to the formula.

V=\frac{1}{3}×3.14×{12}^{2}×19

\large\boxed{V=2863.68 \: {ft}^{3}}

<u>Therefore</u><u>,</u><u> </u><u>the</u><u> </u><u>volume</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>cone</u><u> </u><u>is</u><u> </u><u>2863.6</u><u>8</u><u> </u><u>cubic</u><u> </u><u>feets</u><u>.</u>

5 0
2 years ago
PLEASE HELP!
emmainna [20.7K]

Use the given recursion and starting value of x_0 = 2.4 to find x_1 :

x_1 = \dfrac{x_0 + \frac6{x_0}}2 = \dfrac{2.4 + \frac{6}{2.4}}2 = 2.45

Do the same for x_2 and x_3 :

x_2 = \dfrac{x_1 + \frac6{x_1}}2 = \dfrac{2.45 + \frac6{2.45}}2 \approx 2.44949

x_3 = \dfrac{x_2+\frac6{x_2}}2 \approx \dfrac{2.44949 + \frac6{2.44949}}2 \approx \boxed{2.44949}

(That's not a mistake. This just tells you that the 2nd and 3rd iterates are very close together and have at least the same first 5 digits after the decimal.)

5 0
2 years ago
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