Answer:
a) After the balloon inflated after 440 uL of dropwise due to the reaction of 1-Decene and the solution in the conical vial. b) 
⇒ 16
c) No 
was not the limiting reactant.
Explanation:
Generally, hydrogenation is the chemical reaction between a compound or element and molecular hydrogen in the presence of catalysts such as platinum.
a) After the balloon inflated after 440 uL of dropwise 1-Decene solution was added due to the reaction between 1-Decene and the solution in the conical vial.
b) ⇒ 16
c) was not the limiting reactant based on the mol to mol ratio of and decane which is 1:1. Therefore, if 0.8 mol of decane was produced then 0.8 mol of would also be produced.
If the potassium ions were represented by spheres, the smaller one is the ion and the bigger one is the (neutral) atom.
Generally, metallic atoms (such as potassium) readily form cations (positively-charged ions) by losing electrons in their outer shells. By losing these electrons, the atoms are expected to be smaller in size. However for nonmetals, they readily gain electrons to form anions (negatively-charged ions). By gaining these electrons in their outer orbital shells, the ions generally then becomes larger.
Answer:
3.38 moles of O2.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
4CH2OH + 5O2 → 4CO2 + 6H2O
From the balanced equation above,
4 moles of CH2OH required 5 moles of O2 for complete combustion.
Finally, we shall determine the number of mole of O2 needed to react with 2.7 moles of CH2OH. This can be obtained as follow:
From the balanced equation above,
4 moles of CH2OH required 5 moles of O2 for complete combustion.
Therefore, 2.7 moles of CH2OH will require = (2.7 × 5)/4 = 3.38 moles of O2 for complete combustion.
Thus, 3.38 moles of O2 is required.
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