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OLga [1]
3 years ago
13

hydrogen combines with sulfur much like hydrogen combines with oxygen draw an electron dot diagram showing hydrogen combined wit

h sulfur and write the chemical formula below
Chemistry
1 answer:
sertanlavr [38]3 years ago
6 0

hydrogen combines with sulfur is H2S

<span> hydrogen combines with oxygen H2O</span> <span>Hydrogen sulfide<span> <span>is the </span></span>chemical compound<span> <span>with the </span></span>formula <span>H<span>
2S</span></span>. It is a colorless gas<span> <span>with the characteristic foul odor of rotten </span></span>eggs<span>; it is heavier than air, very poisonous, corrosive, flammable, and explosive; properties shared with the denser </span>hydrogen chalcogenides</span>

<span> </span>

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Use molecular structure and intermolecular bonding to describe why bromine has a lower boiling point than water
kotegsom [21]

Answer:

Bromine mollecules are held together by van der waals forces while a water molecule constitutes both van der waals forces and hydrogen bomnding

Explanation:

This makes the water molecule recquire more heat energy to break the bond thus a higher boiling point while bromine structure requires just litttle heat energy  

3 0
3 years ago
The energy required to ionize boron is 801 kJ/mol. You may want to reference (Pages 93 - 98) Section 2.5 while completing this p
earnstyle [38]

Answer:

The frequency is  f =  2,01 * 10^{15} \  Hz

Explanation:

From the question we are told that

   The energy required to ionize boron is E_b  =  801 KJ/mol

Generally the ionization energy of boron pre atom is mathematically represented as

     E_a  =  \frac{E_b}{N_A}

Here  N_A is the Avogadro's constant with value N_A  =  6.022*10^{23}

So

      E_a  =  \frac{801}{6.022*10^{23}}

=>     E_a  =  1.330 *10^{-18} \  J/atom

Generally the energy required to liberate one electron from an atom is equivalent to the ionization energy per atom and this mathematically represented as

       E =  hf  =  E_a

=>     hf  =  E_a

Here h is the Planks constant with value h = 6.626 *10^{-34}

So

       f =  \frac{1.330 *10^{-18}}{ 6.626 *10^{-34}}

=>      f =  2,01 * 10^{15} \  Hz

8 0
3 years ago
Plz can anyone help me I'm a bit stuck in this one ​
trasher [3.6K]

Answer:

just see if i am not wrong

learning balancing in chemistry it take time

hope i am correct

8 0
2 years ago
Describe the basic particle from which all ements are made
maxonik [38]
The answer for this question is: Atoms
7 0
3 years ago
Read 2 more answers
Predict the effect of adding a non competitive inhibitor to the reaction mixture on the rate of reaction at a high substrate con
Darya [45]

Answer:

A noncompetitive inhibitor can only bind to an enzyme with or without a substrate at several places at a particular point in time

Explanation:

this is because It changes the conformation of an enzyme as well as its active site, which makes the substrate unable to bind to the enzyme effectively so that the efficiency of the enzyme decreases. A noncompetitive inhibitor binds to the enzyme away from the active site, altering/distorting the shape of the enzyme so that even if the substrate can bind, the active site functions less effectively and most of the time also the inhibitor is reversible

8 0
3 years ago
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