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prisoha [69]
3 years ago
9

Define prism and itz colo plz tell me fast​

Physics
2 answers:
Andrei [34K]3 years ago
7 0

Answer:

A prism is a clear crystal that refracts light

Explanation:

Nonamiya [84]3 years ago
3 0
A prism is a transparent optical element with a flat polished surface that refract light (:

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To summarize and analyze data with both a crosstabulation and charting, Excel typically pair
r-ruslan [8.4K]

Answer:

To summarize and analyze data with both a crosstabulation and charting, Excel typically pair  PivotCharts with PivotTables (option b)

Explanation:

Pivot Tables allows us to deal with a high volume of data. This kind of tables are mainly designed to summarize, analyze and explore data in a simple way. Meanwhile, Pivot Charts gives the possibility to visualize the summarizing data provided in PivotTables, enabling the detection of trends, correlations,comparisons and so on. Because of that Pivot tables and pivot charts are usefull and complementary tools of Excel.

Summarizing, the proper option is b.

7 0
3 years ago
Which of the following is equivalent to 4.5 m?
Romashka [77]
We can’t see the following
3 0
3 years ago
speed of sound is 343 Ms at 20 degrees Celsius. The frequency heard from the sound is 256 Hz. what is the sounds wavelength?
Lina20 [59]
S= 343m/s
F=256Hz

WL= 343ms/256-1
WL=V/F

 = 1.339844m     
7 0
3 years ago
For which question could a testable hypothesis be developed?
Mandarinka [93]
I believe it’s B; Theories may be proven to be true and become laws.
A would make sense if we were talking about hypotheses however, we’re not.
8 0
3 years ago
A 0.03 kg golf ball is hit off the tee at a speed of 34 m/s. The golf club was in contact with the ball for 0.003 s. What is the
Liula [17]

Answer:

The average force on ball by the golf club is 340 N.

Explanation:

Given that,

Mass of the golf ball, m = 0.03 kg

Initial speed of the ball, u = 0

Final speed of the ball, v = 34 m/s

Time of contact, \Delta t=0.003\ s

We need to find the average force on ball by the golf club. We know that the rate of change of momentum is equal to the net external force applied such that :

F=\dfrac{\Delta p}{\Delta t}\\\\F=\dfrac{mv-mu}{\Delta t}\\\\F=\dfrac{mv}{\Delta t}\\\\F=\dfrac{0.03\ kg\times 34\ m/s}{0.003\ s}\\\\F=340\ N

So, the average force on ball by the golf club is 340 N.

4 0
4 years ago
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