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Alchen [17]
2 years ago
15

Please help with this i am not good with this

Physics
1 answer:
vagabundo [1.1K]2 years ago
6 0

Answer:

Ball 3 (tennis ball)

Explanation:

Formula we are using :

<u>acceleration = Force / mass</u>

<u />

=============================================================

Ball 1 :

⇒ acceleration = 15 N / 0.5 kg

⇒ acceleration = 30 m/s²

===========================================================

Ball 2 :

⇒ acceleration = 15 N / 4.5 kg

⇒ acceleration = 30/9 m/s²

⇒ acceleration = 10/3 m/s²

⇒ acceleration = 3.33 m/s²

===========================================================

Ball 3 :

⇒ acceleration = 15 N/ 0.05 kg

⇒ acceleration = 300 m/s²

============================================================

On comparing, we see that Ball 3 (tennis ball) has the greatest acceleration.

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How many neutrons does element X have if its atomic number is 48 and its mass number is 167?
lys-0071 [83]
If its atomic number is 48, then it has 48 protons in the nucleus
of each atom.  Any more mass than that is supplied by the neutrons
that are mixed in there with the protons.

If the mass is 167, and 48 of those are protons, then there are

             (167 - 48)  =  119 neutrons

in each nucleus.

6 0
4 years ago
Two point charges, 3.4 μC and -2.0 μC , are placed 5.0 cm apart on the x axis. Assume that the negative charge is at the origin,
Elza [17]

The electric field is zero at x = -16.45cm

Data;

  • q1 = 3.4 μC
  • q2 = -2.0 μC
  • distance = 5cm

<h3>The Electric Field at point 0</h3>

As the 3μC is larger than -2.0μC  and the charges are opposite sign. The electric field will be zero at the negative axis.

Let the point be at x.

For an electric field to be equal to zero;

k(\frac{q_1}{d_1})^2 + k(\frac{q_2}{d_2})^2 = 0\\\frac{3.4}{(5-x)^2} - \frac{2}{x^2} = 0\\

Let's solve for x using mathematical methods.

\frac{3.4x^2 - 2(5-x)^2}{(5-x)^2x^2}= 0\\ 3.4x^2 - 2(5-x^2) = 0\\3.4x^2 - 50 - 2x^2 + 20x = 0\\1.4x^2 +20x - 50 = 0

Solving the above quadratic equation;

x = -16.45cm

The electric field is zero at x = -16.45cm

Learn more on electric field at a point here;

brainly.com/question/1592046

brainly.com/question/14372859

8 0
3 years ago
Most of the mass of the Milky Way exists in the form of:<br> a.) starsb.) gasc.) dustd.) dark matter
Sveta_85 [38]
<h2>Answer: dark matter</h2>

It is believed that the Milky Way has 90% dark matter and only 10% ordinary matter (known matter). Because, like gravity, <u>dark matter can not be observed directly</u>, however its existence is inferred through the movement of the stars and the cosmic dust within the galaxy.

It is important to note that dark matter composition is unknown and corresponds to 80% of the matter in the universe. It does not emit or interact with any type of electromagnetic radiation, but it interacts with the known matter through gravity.  

5 0
3 years ago
A fairground ride spins its occupants inside a flying saucer-shaped container. If the horizontal circular path the riders follow
Oksana_A [137]

Answer:

a)\omega=1.36rad/s

b)\omega=12.99rpm

c)F=705.6N

Explanation:

a) The angular velocity is related to the centripetal acceleration by the formula a_{cp}=\omega^2r, which for our purposes we will write as:

\omega=\sqrt{\frac{a_{cp}}{r}}

Since <em>we want this acceleration to be 1.5 times that due to gravity</em>, for our values we will have:

\omega=\sqrt{\frac{1.5g}{r}}=\sqrt{\frac{(1.5)(9.8m/s^2)}{(8m)}}=1.36rad/s

b) 1 rpm (revolution per minute) is equivalent to an angle of 2\pi radians in 60 seconds:

1\ rpm=\frac{2\pi rad}{60s} =\frac{\pi}{30}rad/s

Which means <em>we can use the conversion factor</em>:

\frac{1\ rpm}{\frac{\pi}{30}rad/s}=1

So we have (multiplying by the conversion factor, which is 1, not affecting anything but transforming our units):

\omega=1.36rad/s=1.36rad/s(\frac{1\ rpm}{\frac{\pi}{30}rad/s})=12.99rpm

c) The centripetal force will be given by Newton's 2nd Law F=ma, so on the centripetal direction for our values we have:

F=ma=(48kg)(1.5)(9.8m/s^2)=705.6N

8 0
3 years ago
A bullet of mass 0.107 kg traveling horizontally at a speed of 300 m/s embeds itself in a block of mass 3 kg that is sitting at
melisa1 [442]

Answer:

165.77J

Explanation:

M₁ = 0.107kg

u₁ = 300m/s

m₂ = 3kg

u₂ = 0

v =

m₁u₁ + m₂u₂ = (m₁ + m₂)V

(0.107*300) + 0 = (0.107 + 3)V

V = 32.1 / 3.107 = 10.33m/s

kinetic energy of the system after collision =

½m1v² + ½m2v²

K.E = ½(m1 + m2)v²

K.E = ½(0.107+3) * 10.33²

K.E = 165.77J

5 0
3 years ago
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