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Alchen [17]
3 years ago
15

Please help with this i am not good with this

Physics
1 answer:
vagabundo [1.1K]3 years ago
6 0

Answer:

Ball 3 (tennis ball)

Explanation:

Formula we are using :

<u>acceleration = Force / mass</u>

<u />

=============================================================

Ball 1 :

⇒ acceleration = 15 N / 0.5 kg

⇒ acceleration = 30 m/s²

===========================================================

Ball 2 :

⇒ acceleration = 15 N / 4.5 kg

⇒ acceleration = 30/9 m/s²

⇒ acceleration = 10/3 m/s²

⇒ acceleration = 3.33 m/s²

===========================================================

Ball 3 :

⇒ acceleration = 15 N/ 0.05 kg

⇒ acceleration = 300 m/s²

============================================================

On comparing, we see that Ball 3 (tennis ball) has the greatest acceleration.

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2. A hydraulic lift is used to lift heavy machine pushing down on a 5 square meters piston with a force of 1000 N. What force ne
IRINA_888 [86]

Answer:

The force needs to be applied on the 1 square meter piston to lift the machine is 200 N.

Explanation:

Given that,

Force, F_1=1000\ N

Area, A_1=5\ m^2

We need to find the force needs to be applied on the 1 square meter piston to lift the machine. We know that the pressure at every point is same due to Pascal's law such that :

P_1=P_2\\\\\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\\\\dfrac{1000}{5}=\dfrac{F_2}{1}\\\\F_2=200\ N

So, the force needs to be applied on the 1 square meter piston to lift the machine is 200 N. Hence, this is the required solution.

3 0
4 years ago
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g As they reach higher temperatures, most semiconductors... Selected Answer: have an increased resistance. Answers: have a const
pochemuha

Answer:

have an increased resistance

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3 years ago
A ball of mass m is thrown into the air in a 45° direction of the horizon, after 3 seconds the ball is seen in a direction 30° f
Rzqust [24]

Answer:

Velocity (magnitude) is 98.37 m/s

Explanation:

We use the vertical component of the initial velocity, which is:

v_{0y}=v_0*sin(45)=\frac{\sqrt{2} }{2}v_0

Using kinematics expression of vertical velocity (in y direction) for an accelerated motion (constant acceleration, which is gravity):

v_{y}=v_{0y}+a*t=\frac{\sqrt{2} }{2}v_0-9.8t

Now we need to find v_y as a function of v_0. We use the horizontal velocity, which is always the same as follow:

v_x=v_0cos(45\º)=\frac{\sqrt{2} }{2}v_0=v_{t=3}*cos(30\º) \\

We know the angle at 3 seconds:

v_y(t=3)=v_{t=3}*sin(30\º)\\v_{t=3}=\frac{v_y}{sin(30\º)}

Substitute  v_{t=3} in  v_x and then solve for  v_y

\frac{\sqrt{2} }{2}v_0=\frac{v_y*cos(30\º) }{sin(30\º)} \\v_y=\frac{\sqrt{6} }{6}v_0

With this expression we go back to the kinematic equation and solve it for initial speed

\frac{\sqrt{6} }{6} v_0 =\frac{\sqrt{2} }{2}v_0-29.4\\v_0(\frac{\sqrt{6}-3\sqrt{2}}{6} )=-29.4\\v_0=98.37 m/s

3 0
4 years ago
Greatest to least 56.2,56.32,56.321
Juli2301 [7.4K]
56.321, 56.32, 56.2 is the answer
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3 years ago
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How big is the image produced by the periscope compared to the size of the object
ipn [44]

<span>As long as both mirrors are set at 45% and the same size then you see the same as is reflected in the upper mirror </span>

<span>Put a lens in the middle of the tube </span>

<span>? </span>

<span>We use mirrors when we drive cars ect </span>

<span>Normally they are set across from a concealed entrance or one that is hard to see both ways like the inside of a hairpin bend. Sometimes only to help in one direction. </span>

<span>Sonar which is sound waves that are sent out at a set rate then reflected by objects. The longer the gap between the two the further away it is, They still use periscopes to target boats though. </span>

<span>The periscope can only reflect what is outside so if you could see it because there is enough light then Yes. If you could not see it because it is dark then No unless you get into Info-Red light or Image Intensifying systems as well </span>
8 0
3 years ago
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