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2 years ago

Please help with this i am not good with this

Physics

1 answer:

vagabundo [1.1K]2 years ago

6 0

Answer:

Ball 3 (tennis ball)

Explanation:

Formula we are using :

acceleration = Force / mass

=============================================================

Ball 1 :

⇒ acceleration = 15 N / 0.5 kg

⇒ acceleration = 30 m/s²

===========================================================

Ball 2 :

⇒ acceleration = 15 N / 4.5 kg

⇒ acceleration = 30/9 m/s²

⇒ acceleration = 10/3 m/s²

⇒ acceleration = 3.33 m/s²

===========================================================

Ball 3 :

⇒ acceleration = 15 N/ 0.05 kg

⇒ acceleration = 300 m/s²

============================================================

On comparing, we see that Ball 3 (tennis ball) has the greatest acceleration.

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3 years ago

A block is attached to the end of a horizontal ideal spring and rests on a frictionless surface. The block is pulled so that the

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Answer:

The answer is "a, c and b"

Explanation:

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4 0

3 years ago

Through Newton’s third law of motion, we know that if a rocket ship pushes down on the ground, the ground will push back up on t

vova2212 [387]

C.
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3 years ago

A pulley lifts a 72-N load with a force of 24-N. The input distance is 2m and the output distance is 0.5m. What is the efficienc

Debora [2.8K]

Answer:

Explanation:

Work done on the lever ( input energy ) = force applied x input distance

= 24 N x 2m = 48 J

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= 72 N x 0.5m = 36 J

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3 years ago

You are comparing two diffraction gratings using two different lasers: a green laser and a red laser. You do these two experimen

Nikolay [14]

Answer:

a. (a) grating A has more lines/mm; (b) the first maximum less than 1 meter away from the center

Explanation:

Let n₁ and n₂ be no of lines per unit length of grating A and B respectively.

λ₁ and λ₂ be wave lengths of green and red respectively , D be distance of screen and d₁ and d₂ be distance between two slits of grating A and B ,

Distance of first maxima for green light

= λ₁ D/ d₁

Distance of first maxima for red light

= λ₂ D/ d₂

Given that

λ₁ D/ d₁ = λ₂ D/ d₂

λ₁ / d₁ = λ₂ / d₂

λ₁ / λ₂ = d₁ / d₂

But

λ₁ < λ₂

d₁ < d₂

Therefore no of lines per unit length of grating A will be more because

no of lines per unit length ∝ 1 / d

If grating B is illuminated with green light first maxima will be at distance

λ₁ D/ d₂

As λ₁ < λ₂

λ₁ D/ d₂ < λ₂ D/ d₂

λ₁ D/ d₂ < 1 m

In this case position of first maxima will be less than 1 meter.

Option a is correct .

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3 years ago