The change in momentum of the bullet : 59.52 kg m/s
Given
m=0.06 kg
Δt=0.025 s
vo=0(from rest)
vt= 992 m/s
Required
The change in momentum
Solution
The change in momentum = ΔP
ΔP =m(vt-vo)
ΔP =0.06(992-0)
ΔP =59.52 kg m/s
Answer:
the same.
hope this helps!
a) 1156.8 lb
b) 130.7 lb
Explanation:
See attachment
190.3759 pounds
If the astronaut weighs 210 pounds when he is at a distance of 3978 miles from the Earth's center, then he will weigh
210 [3978 / (3978 + 200) ]² = 190.3759 pounds
at an altitude of 200 km.
R1=R2=R3=R4=10 ohms
V=IR
V=2.10
V=20v