A. Units
the rest can be understand that he did not clarify
Answer:
1210 N/m between the inner and outer edges (repulsive)
252.59 N/m between inner and line charges (attractive)
1210+252.59=1462.59 N/m effective force/metre on the inner edge
Explanation:
f=k*Qq/r^2 was applied, the charges are concentrated at the edges of a ring both inner and the outer were shape edges with uniform charge densities 6.6 micro C/m of distance 4.5-2.7=1.8 cm
Hey!
Formula for calculating work = Force × distance
Work done = Force applied on the object × distance travelled by it.
Hope it helps...!!!
This is a concrete example of the Doppler effect. This effect is the change of frequency experienced by the listener or the observer with respect to their relative distance to the source of the sound. There can be two equations to be applied: to the approaching source, and to the receding source.
Approaching source:
frequency observed = [v/(v-v,source)]*frequency of source, where v is the velocity of sound . Substituting,
1000 = [340/(340-v,source)]*frequency of source <---- equation 1
Receding source:
frequency observed = [v/(v+v,source)]*frequency of source, where v is the velocity of sound . Substituting,
800 = [340/(340+v,source)]*frequency of source <---- equation 2
Rearranging equation 1: [1000(340-v,source)]/340 = frequency of source
Equation 2: 800 = [340/(340+v,source)]*frequency of source
Substituting equation 1 to equation 2:
800 = [340/(340+v,source)]*[1000(340-v,source)]/340
Solving using the scientific calculator under shift-solve feature,
v,source = 37.78 m/s
Therefore, the train is moving at 37.78 m/s.
Answer:
The answer would be 450 m kg/s
Explanation/ Explanation / Example:
Provided an object traveled 500 meters in 3 minutes , to calculate the average velocity you should take the following steps: Change minutes into seconds (so that the final result would be in meters per second). 3 minutes = 3 * 60 = 180 seconds , Divide the distance by time: velocity = 500 / 180 = 2.77 m/s .
If this doesn't help let me know!