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kap26 [50]
3 years ago
8

Connecting many devices in a single socket does not affect the flow of current in a

Physics
1 answer:
eimsori [14]3 years ago
7 0

<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>:</u><u>-</u><em> </em><em>F</em><em>a</em><em>l</em><em>s</em><em>e</em>

<u>E</u><u>x</u><u>p</u><u>l</u><u>a</u><u>n</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u>

<em>False because it can leads to overloading and further to short circut.</em>

<h2><em><u>H</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>I</u></em><em><u>t</u></em><em><u> </u></em><em><u>W</u></em><em><u>i</u></em><em><u>l</u></em><em><u>l</u></em><em><u> </u></em><em><u>H</u></em><em><u>e</u></em><em><u>l</u></em><em><u>p</u></em><em><u> </u></em><em><u>Y</u></em><em><u>o</u></em><em><u>u</u></em><em><u>!</u></em></h2>
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Suppose that 2 scientists use different measurement systems in their work. What problems might arise if they shared their data?
bixtya [17]
<span>In assumption that there were two scientists who used different measurement systems in their research. The problems that might arise if they shared their data is obviously and primarily error. Errors are recognized and one element in every measure, system and quantity. Error was already even present in the measurement system alone a scientist used and it will furthermore aggregate, when these two different scales are combined the more error escalates in the process. There are two types: random and systematic error.   </span>



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4 years ago
A car accelerates uniformly from rest to a speed of 10m/s. Calculate its acceleration
Maurinko [17]

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Give four examples of landforms where both the water and the land around it are flat.

Explanation:

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3 years ago
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3 years ago
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3 years ago
Find the length (in m) of an organ pipe closed at one end that produces a fundamental frequency of 494 Hz when air temperature i
elena-14-01-66 [18.8K]

Answer:

0.173 m.

Explanation:

The fundamental frequency of a closed pipe is given as

fc = v/4l .................. Equation 1

Where fc = fundamental frequency of a closed pipe, v = speed of sound  l = length of the pipe.

Making l the subject of the equation,

l = v/4fc ................ Equation 2

also

v = 331.5×0.6T ................. Equation 3

Where T = temperature in °C, T = 18.0 °c

Substitute into equation 3

v = 331.5+0.6(18)

v = 331.5+10.8

v = 342.3 m/s.

Also given: fc = 494 Hz,

Substitute into equation 2

l = 342.3/(4×494)

l = 342.3/1976

l =0.173 m.

Hence the length of the organ pipe = 0.173 m.

7 0
3 years ago
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