All you have to do is plug m and n into the equation:
n+6m
Since n=7, you'll get:
7+6m
And since m=8, you'll get:
7+6(8)
And by doing the order of operations (PEMDAS), you'll start off multiplying 6 and 8, which is 48, then add 7, which is 55.
Your answer should be 55!
Answer:
I think [(-4)^4]^5, but I'm not completely sure
Step-by-step explanation:
1.0995116e+12 greater than -4.7223665e+21
[(-4)^4]^5=1.0995116e+12
-[(4^12)^3=-4.7223665e+21
Answer:
change in the total cost for each book printed = $15
cost to get started (before books are bought) = $1200
Step-by-step explanation:
IF the eqn is y = 15x +1200
where y represent the total cost of publishing a book (in dollars) and
x represent the number of copies of the book printed
then cost to get started (before books are bought) can be found by substitute x=0 into the eqn
y = 1200 + 15*0 = $1200
change in the total cost for each book printed will be the difference in total cost at x=0 and x=1
when x=0, y=1200
when x=1, y=1200+15*1=1215
so the change in total cost=$15
Answer:
- amount lent: ₹6000
- interest received: Kamal, ₹600; Anand, ₹615.
Step-by-step explanation:
For principal P invested at simple interest rate r, the returned value in t years is ...
A = P(1 +rt)
If K is Kamal's returned value, the given numbers tell us ...
K = P(1 +0.05·2) = 1.1P
__
For principal P invested at compound interest rate r, with interest compounded annually for t years, the returned value is ...
A = P(1 +r)^t
If A is Anand's returned value, the given numbers tell us ...
A = P(1.05)² = 1.1025P
This latter amount is RS.15 more than the former one, so we have ...
1.1025P = 1.1P +15
0.0025P = 15 . . . . . . . . subtract 1.1P
P = 6000 . . . . . . . . . . . divide by 0.0025 . . . . the amount lent
Kamal received 1.1P -P = 0.1P = 600 on the investment.
Each lent ₹6000. Kamal received ₹600 in interest; Anand received ₹615 in interest.
