Answer:
Aldehydes are typically more reactive than ketones due to the following factors. ... The carbonyl carbon in aldehydes generally has more partial positive charge than in ketones due to the electron-donating nature of alkyl groups. Aldehydes only have one e- donor group while ketones have two.
Explanation:
Hey there :
Molar mass of NaCl = 58.44 g/mol
Number of moles :
n = mass of solute / molar mass
n = 58 / 58.44
n = 0.9924 moles of NaCl
Volume = 1.0 L
Therefore:
Molarity = number of moles / volume ( L )
Molarity = 0.9924 / 1.0
Molarity = 0.9924 M
Hope that helps!
EASY AS PIE AND I LIKE PIE
Calcium iodide (CaI2) is an ionic bond, which means that electrons are transferred. In order for Ca to become the ion Ca2+, the calcium atom must lose 2 electrons. (Electrons have a negative charge, so when an atom loses 2 electrons, its ion becomes more positive.) In order for I to become the ion I1−, the iodine atom must gain 1 electron. (When an atom gains an electron, its ion will be more negative.) However, the formula for calcium iodide is CaI2 - there are 2 iodine ions present. This makes sense because the iodine ion has a charge of -1, so two iodine ions have to be present to cancel out the +2 charge of the calcium ion. Therefore, the calcium atom transfers 2 valence electrons, one to each iodine atom, to form the ionic bond.
IF WRONG, SORRY
Answer:
The correct answer is option D which is the decreasing order of conductivity is Mn, O, Ge.
Explanation:
You can easily answer this if you know the periodic trends. For the property of electrical conductivity, it decreases across a period and decreases also down a group. Thus, the most conductive element must be Mn, while the least conductive one is Ge. So, the answer is: -Mn, O, Ge
