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adelina 88 [10]
3 years ago
11

What would change oxygen into another isotope

Chemistry
1 answer:
Ainat [17]3 years ago
5 0

Answer:

Adding Neutrons

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Atoms Composition
  • Nucleus - Protons, Neutrons
  • Electrons

Explanation:

We know that adding Protons to any atom will change its chemical properties and make it a different element.

We also know that adding Electrons to any atom will simply only change its overall charge.

Isotopes are formed by adding <em>neutrons</em> to the nucleus. It will be the same element but it would have a different mass and amount of neutrons.

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What is the composition, in atom percent, of an alloy that consists of a) 5.5 wt% Pb and b) 94.5 wt% of Sn? Assume that the atom
Anastaziya [24]

Answer : The percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

Explanation :

First we have to calculate the number of atoms in 5.5 wt% Pb and 94.5 wt% of Sn.

As, 207.2 g of lead contains 6.022\times 10^{23} atoms

So, 5.5 g of lead contains \frac{5.5}{207.2}\times 6.022\times 10^{23}=1.59\times 10^{22} atoms

and,

As, 118.71 g of lead contains 6.022\times 10^{23} atoms

So, 94.5 g of lead contains \frac{94.5}{118.71}\times 6.022\times 10^{23}=4.79\times 10^{23} atoms

Now we have to calculate the percent composition of Pb and Sn in atom.

\% \text{Composition of Pb}=\frac{\text{Atoms of Pb}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100

\% \text{Composition of Pb}=\frac{1.59\times 10^{22}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=3.21\%

and,

\% \text{Composition of Sn}=\frac{\text{Atoms of Sn}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100

\% \text{Composition of Sn}=\frac{4.79\times 10^{23}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=96.8\%

Thus, the percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

6 0
3 years ago
Examine the following equations.
Zigmanuir [339]

Answer:

A and B

Explanation:

This is because there was emission of gamma (Y) radiations in both the reactions.

8 0
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To balance the reaction what coefficients (numbers) are needed: HBr +KOH ---&gt; KBr + H2O
Tom [10]

Answer:

H2Br + 2KOH ----- K2Br + 2H2O

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3 years ago
What claim is being made?
dangina [55]
The correct answer is c
7 0
3 years ago
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Write METAL, NONMETAL, DIATOMIC MOLECULE ,METALLOID
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Alkali metal - Group 1 metal
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3 years ago
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