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Travka [436]
4 years ago
12

How do dominant and recessive traits impact genotype and phenotype?

Chemistry
1 answer:
beks73 [17]4 years ago
7 0
The phenotype depends on the dominant allele. Only people with aa genotype will express recessive traits. Hope this helped!
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Which statements about complex IV are true? 1) This complex catalyzes the reduction of oxygen to water. 2) Despite consuming pro
Brrunno [24]

Answer:

The answer is 1, 2, 3 for the first question and 1,2,3 again for the second question.

Explanation:

The true statements about complex IV are:

1) This complex catalyzes the reduction of oxygen to water.

2) Despite consuming protons, this complex pumps H+ across the membrane at a rate of 4 per molecule of O2 reduced.

3) The protons flow across a gradient to the inner membrane space.

The true statemennts about complex IV are:

1) This complex catalyzes the reduction of oxygen to water.

2) Despite consuming protons, this complex pumps H+ across the membrane at a rate of 4 per molecule of O2 reduced.

3) The protons flow across a gradient to the inner membrane space.

6 0
3 years ago
Minerals with the silicon-oxygen structure shown in Figure 2-1 are classified into what group?
Snowcat [4.5K]

Answer : Option D) Silicates.

Explanation : The minerals with the silicon-oxygen structures are classified as silicates.

As per the definition, A silicate is any member of a family which has anions consisting of silicon and oxygen, usually they have the general formula as [SiO].

It usually has a structure which has a central silicon ion which has a charge of (+4) while each oxygen has a charge of negative two (-2) and thus each silicon-oxygen bond is equal to one half (1/2) of the total bond energy of oxygen. Therefore, it confirms that the answer is Silicates.

3 0
3 years ago
Positive Deviation from Raoult's Law occurs when the vapour pressure of component is greater than what is expected in Raoult's L
8090 [49]

Answer:

All of the above.

Explanation:

In positive deviation from Raoult's  Law occur when the vapour pressure of components is greater than what is expected value in Raoult's law.

When a solution is non ideal then it shows positive or negative deviation.

Let two solutions A and B to form non- ideal solutions.let the vapour pressure  of component A is P_A and vapour pressure of component B is P_B.

P^0_A= Vapour pressure of component A in pure form

P^0_B= Vapour pressure of component B in pure form

x_A=Mole fraction of component A

x_B==Mole fraction of component B

The interaction between A- B is less than the interaction A- A and B-B interaction.Therefore, the escaping tendency of liquid molecules in mixture is greater than the escaping tendency in pure form.Hence, the vapour pressure of a mixture is greater than the initial value of vapour pressure.

P_A >P^0_A\cdot x_A,P_B>P^0_B\cdot x_B

Therefore, P_A+P_B >P^0_A\cdot x_A+P^0_B \cdot x_B

Therefore, the enthalpy of mixing is greater than zero and change in volume is greater than zero.

Hence, option a,b,c and d are true.

6 0
3 years ago
Phenolphthalein solution is used as an indicator of acids and bases. If added to an ammonia-based solution of window cleaner, we
77julia77 [94]
C.) pink <span>In a </span>base<span>, with a pH> 8.2, we would expect the </span>indicator<span> to turn </span>pink. Phenolphthalein<span> is colorless in an acidic or neutral </span>solution<span>; it turns from pink to fuchsia in a basic </span>solution<span>. Cleaners and </span>products<span> containing soaps, are </span>bases<span>.</span>
8 0
3 years ago
Read 2 more answers
How many amperes would be needed to produce 60.0 grams of magnesium during the electrolysis of molten mgcl 2 in 2.00 hours?
Shalnov [3]

Answer:

\boxed{\text{66.2 A}}

Explanation:

1. Write the equation for the reaction.

M_r:                 24.30

          MgCl₂ ⟶ Mg + Cl₂

m/g:                   60.0

2. Calculate the moles of Mg

Moles of Mg = 60.0 g Mg × (1 mol Mg/ 24.30 g Mg) = 2.469 mol Mg

3. Calculate the moles of electrons

Moles of electrons = 2.469 mol Mg × (2 mol electrons/1 mol Mg)

= 4.938 mol electrons

4. Calculate the number of coulombs

Q = 4.938 mol electrons × (96 485 C/1 mol electrons) = 476 500 C

5. Calculate the current required

Q  = It

I = Q/t

t = 2.00 h × (60 min/1h) × (60 s/1 min) = 7200 s

I = 476 500 C/7600 s= 66.2 C/s = 66.2 A

You need a current of \boxed{\textbf{66.2 A}}.

8 0
4 years ago
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