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mina [271]
3 years ago
12

Which sample of matter has a crystal structure?

Chemistry
1 answer:
Maurinko [17]3 years ago
4 0
The correct answer:C) NaCl(s)
Hope this helps!
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An empty beaker weighs 25.91 g. When completely filled with water, the beaker and its contents have a total mass of 333.85 g. Wh
Finger [1]

Answer:

The beaker holds 307.94  mL

Explanation:

As we know that the volume that beaker hold is the volume of water that occupied by it.

For this first we have to find mass of the water in the beaker

This can be calculated by the subtraction of beaker's weight from the weight of beaker and water.

     weight of water (m) = total weight - weight of beaker

Empty weight of beaker = 25.91 g

Weight of beaker with water = 333.85 g

Weight of water = 333.85 - 25.91 = 307.94 g

Density of water = 1 g/mL

We have

      Mass = Volume x density

      307.94  = Volume x 1

      Volume = 307.94  mL

The beaker holds 307.94  mL

3 0
3 years ago
5. How many grams of CuCl2 are required to make 75 mL of a 0.20M solution?
Effectus [21]
35.8 cuc12 jk jk ok jk
5 0
2 years ago
PLEASE HELP, CHEMISTRY!!! 20 POINTS!!!
mart [117]

the answer is in the picture

6 0
3 years ago
Read 2 more answers
The pathogen below is a single-celled organism without a nucleus that can cause illness in a humans.
sukhopar [10]

Answer:

bacteria

Explanation:

The pathogen below is a single-celled organism without a nucleus that can cause illness in a humans.

3 0
2 years ago
Rusting of iron is a very common chemical reaction. It results in one form from Fe reacting with oxygen gas to produce iron (III
Vlada [557]

<u>Answer:</u> The given amount of iron reacts with 9.0 moles of O_2 and produce 6.0 moles of Fe_2O_3

<u>Explanation:</u>

We are given:

Moles of iron = 12.0 moles

The chemical equation for the rusting of iron follows:

4Fe+3O_2\rightarrow 2Fe_2O_3

  • <u>For oxygen gas:</u>

By Stoichiometry of the reaction:

4 moles of iron reacts with 3 moles of oxygen gas

So, 12.0 moles of iron will react with = \frac{3}{4}\times 12.0=9.0mol of oxygen gas

  • <u>For iron (III) oxide:</u>

By Stoichiometry of the reaction:

4 moles of iron produces 2 moles of iron (III) oxide

So, 12.0 moles of iron will produce = \frac{2}{4}\times 12.0=6.0mol of iron (III) oxide

Hence, the given amount of iron reacts with 9.0 moles of O_2 and produce 6.0 moles of Fe_2O_3

5 0
3 years ago
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